EP CAMPBELL BIO.IN FOCUS AP-MOD.MASTER.
3rd Edition
ISBN: 9780137453092
Author: Urry
Publisher: SAVVAS L
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Chapter 18.5, Problem 2CC
Summary Introduction
To explain:
How multiple exons might have arisen in the ancestral EGF and fibronectin genes, with reference to the data provided in the “Figure 18.14”.
Introduction:
The part of the gene that encodes for RNA is known as exon. During RNA splicing the non-coding part introns are removed and the exons are covalently bond to generate mature mRNA (messenger RNA). Just as the genome is the entire set of gene, exome is the entire set of exons.
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Explain how the following mutations would affect transcription of the yeast GAL1 gene in the presence of galactose. (a) A deletion within the GAL4 gene that removes the region encoding amino acids 1 to 100. (b) A deletion of the entire GAL3 gene. (c) A mutation within the GAL80 gene that blocks the ability of Gal80 protein to interact with Gal3p. (d) A deletion of one of the four UASG elements upstream from the GAL1 gene. (e) A point mutation in the GAL1 core promoter that alters the sequence of the TATA box.
What are the functions of transcriptional activator proteins and repressor proteins? Explain how they work at the molecular level.
a)
hours: 0 2 567
DMC1
SPS1
hours: 0 2 5 6 7 9 11
DIT1
SPS100
Oxygen level (% normal)
b)
120
100
FIGURE 4.6. Comparison of Northern blots with DNA microarray
data. a) Results from four individual Northern blots examining four different
genes and measuring mRNA production over time, as indicated. b) Results
from a series of microarrays for the same four genes of interest. Note the color
scale on the bottom of b), where bright green indicates a 20-fold repression
and bright red indicates a 20-fold induction. Black indicates no change in
transcription (i.e., the merged microarray spot would have appeared yellow).
80
60
40
20
0 1 2
gene X
gene Y
gene Z
3
1
hour
1.0
1.0
b)
1.0
hours: 0.5 2 5 7 9 11
DMC1
SPS1
DIT1
SPS100
fold repressed
>20 10x 3x3x10x >20
1:1
fold induced
4 5 6 7 8 9 10 11
Time (hours)
3
hour
2.2
4.5
1.5
5
9
hour
hour
1.0
0.15
0.95 0.05
2.0
2.0
FIGURE 4.7 Transcriptional response of three genes
to the gradual loss of oxygen. a) Graph of oxygen con-
sumption over time by…
Chapter 18 Solutions
EP CAMPBELL BIO.IN FOCUS AP-MOD.MASTER.
Ch. 18.1 - Prob. 1CCCh. 18.2 - Prob. 1CCCh. 18.2 - Explain the advantage of the systems biology...Ch. 18.2 - Prob. 3CCCh. 18.3 - The best estimate is that the human genome...Ch. 18.3 - Prob. 2CCCh. 18.3 - Prob. 3CCCh. 18.4 - Discuss the characteristics of mammalian genomes...Ch. 18.4 - Which of the three mechanisms described in Figures...Ch. 18.4 - Prob. 3CC
Ch. 18.5 - Describe three examples of errors in cellular...Ch. 18.5 - Prob. 2CCCh. 18.5 - Prob. 3CCCh. 18.6 - Would you expect the genome of the macaque (a...Ch. 18.6 - Prob. 2CCCh. 18 - Prob. 1TYUCh. 18 - Prob. 2TYUCh. 18 - Two eukaryotic proteins have one domain in common...Ch. 18 - DRAW IT Comparing amino acid sequences of similar...Ch. 18 - SCIENTIFIC INQUIRY The scientists mapping human...Ch. 18 - FOCUS ON EVOLUTION Genes important in the...Ch. 18 - FOCUS ON INFORMATION The continuity of life is...Ch. 18 - SYNTHESIZE YOUR KNOWLEDGE Insects have three...
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- Why is the ErbB family pathway an important pathway for researchers that target cancer therapy. explain in 3-5 sentences.arrow_forwardSearching the yeast Saccharomyces cerevisiae genome, researchers found approximately 4,000 DNA sites with a sequence which could potentially bind the yeast transcription factor GAL4. GAL4 activates the transcription of galactose genes. Yet there are only 10 GAL4-binding sites which control the genes necessary for galactose metabolism. The GAL4 binding sequence is CGGAT#AGAAGC*GCCG, where # is T, C or G, and * is C or T. In one chromatin immunoprecipitation experiment (ChIP), yeast growing on galactose were lysed, and subjected to cross-linking reagents which cross-linked transcription factors and activators to DNA. Next the DNA was sheared into small fragments, and antibodies to GAL4 were added. These antibodies coprecipitated the GAL4 and the DNA it was cross-linked to. The cross-linking was then chemically reversed, and the DNA was isolated, cloned into a library of plasmids and sequenced. Results showed that only 10 different DNA sequences had GAL4 bound. Since the…arrow_forwardIn the module, you have learned about P-element mediated transgenesis in Drosophila and the concept of using transgenes to rescue mutant phenotypes. In the figure below, you will see a wild type fly with its natural eye colour and three mutants with their eye colours changed to vermillion, white and rosy, respectively. A schematic of P-element mediated transgenesis (as shown in the lectures) is also included in the figure. Please inspect the schematic carefully and choose which of the following statements is true: I. Injection of the white experimental transgene into the vermillion mutant embryo will not change the vermillion mutant phenotype II. Injection of the white experimental transgene in the rosy mutant embryo will change rosy eye colour to red (wild type) III. Injection of the white experimental transgene in the white mutant embryo will not change the white mutant phenotype IV. Injection of the white experimental transgene in the rosy mutant…arrow_forward
- The diagram below shows a closeup of regulatory proteins binding to one of the UASG elements near the GAL7, GALI0, and GALI genes, which code for the protein products needed for yeast to use the sugar galactose. The red triangle symbolizes an "effector" molecule that binds to Gal80p. In this hypothesis (which has since been shown to be incorrect), what could be happening to Gal80p when it is bound to the effector molecule that causes it to change its position and uncover the Gal4p transcriptional activation domain. Hint: think about what effector molecules do upon binding to proteins such as the the Lac repressor protein or the CAP protein. Galactose absent, glucose absent Gal80p. _Activation domain Gal4p dimer -Binding domain UASG Galactose present, glucose absent Activation domain Gal80p- Binding domain UASG For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac).arrow_forwardBased on Figure 9-19, can you predict the position of amutation that would affect the synthesis of one isoformbut not the other?arrow_forwardDescribe how transcription would be affected in the Galactose metabolizing pathway in Yeast in the presence of the following mutations. 1. A mutation that resulted in an inability of Gal80 to enter the nucleus. 2. A mutation that resulted in a lack of ability of Gal3 to bind galactose.arrow_forward
- Direct mutagenesis of Ca2+ ATPase gene resulted in the replacement of two amino acid residues - Asn111 and Asn114 to Ala. These substitutions led to the reduction in Ca2+ transport activity by 10% and 50%, respectively. On the other hand, directed mutagenesis that resulted in the alteration of four Glu residues in the lumenal loop of this transport protein to Ala, did not affect the Ca2+ transport. Provide the possible explanation for the observed differences in the Ca2+ transport activity between the protein with Asn->Ala substitution and the protein with Glu->Ala substitution.arrow_forwardIn Figure 9-12(b), what do you think happens to the tRNA that is released from the E site?arrow_forwardThe transcription factor Pax6 is required continually during the life of a mouse (or a human) for the development of the retina. Homozygous Pax6 knockout mice die soon after birth because Pax6 protein is also required in essential organs, such as the pancreas. a) In order to study the role of Pax6 in eye development a researcher wants to generate a mouse that expresses Pax6 everywhere except in its eyes. Describe how you could construct such a mouse by floxing the gene. Is it possible to achieve the same end with a transgene? (Hint: think about using cDNA and RNAI) b) Suppose you want to create a mouse similar to that in part (a), but one where the eye cells from Pax6 function has been removed and now express a gene that specifies a green fluorescent protein (GFP). Marking the cells in this way will allow the investigators to see the shapes of the Pax6- eye cells more easily than if they did not express GFP. Diagram a Pax6 gene construct that would enable the researcher to do this…arrow_forward
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