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Electrical Motor Controls for Integrated Systems
5th Edition
ISBN: 9780826912268
Author: Gary Rockis;Glen A. Mazur
Publisher: American Technical Publishers
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Chapter 18.5, Problem 1CP
To determine
To explain: The least expensive type of transition method.
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A professor teaches two sections of a course:
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c) If a part is found to be defective, what is the probability it came from Machine A?
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- A Factory produces light bulbs from two different machines: Machine A and Machine B. The probability that a randomly selected light bulbs is from Machine A is 60%, and the probability that a light bulb is defective is 5%. Suppose that probability that a light bulb is defective given that it was made by Machine A is 0.05. Similarly, the probability that a light bulb is defective given that it was made by Machine B is 0.03. Are the events “the light bulb is from Machine A” and “the light bulb is defective” independent?arrow_forward3 (10pts). A Factory produces light bulbs from two different machines: Machine A and Machine B. The probability that a randomly selected light bulbs is from Machine A is 60%, and the probability that a light bulb is defective is 5%. Suppose that probability that a light bulb is defective given that it was made by Machine A is 0.05. Similarly, the probability that a light bulb is defective given that it was made by Machine B is 0.03. Are the events "the light bulb is from Machine A" and "the light bulb is defective" independent?arrow_forwardPlease see the followinggn imagearrow_forward
- A17)arrow_forwardUsing Carson's rule, determine the transmission bandwidth for commercial FM radio broadcasting, provided that the maximum value of frequency deviation is 75 kHz and the bandwidth of the audio signal is 15 kHzarrow_forward2. Laboratory Preliminary Discussion First-order High-pass RC Filter Analysis The first-order high-pass RC filter shown in figure 3 below represents all voltages and currents in the time domain. We will again convert the circuit to its s-domain equivalent as shown in figure 4 and apply Laplace transform techniques. ic(t) C vs(t) i₁(t) + + vc(t) R1 ww Vi(t) || 12(t) V2(t) R₂ Vout(t) VR2(t) = V2(t) Figure 3: A first-order high-pass RC filter represented in the time domain. Ic(s) C + Vs(s) I₁(s) + + Vc(s) R₁ www V₁(s) 12(s) V₂(s) R₂ Vout(S) = VR2(S) = V2(s) Figure 4: A first-order high-pass RC filter represented in the s-domain. Again, to generate the s-domain expression for the output voltage, You (S) = V2 (s), for the circuit shown in figure 4 above, we can apply voltage division in the s-domain as shown in equation 2 below. Equation 2 will be used in the prelab computations to find an expression for the output voltage, xc(t), in the time domain. equation (2) R₂ Vout(s) = V₂(s) = R₂+…arrow_forward
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