![OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)](https://s3.amazonaws.com/compass-isbn-assets/textbook_empty_images/large_textbook_empty.svg)
OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)
5th Edition
ISBN: 9781285460420
Author: John W. Moore; Conrad L. Stanitski
Publisher: Cengage Learning US
expand_more
expand_more
format_list_bulleted
Question
Chapter 18.4, Problem 18.7PSP
Interpretation Introduction
Interpretation:
Age of sealed sample of Scotch whiskey has to be estimated if it contains tritium content 0.60 time that of water.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The amount of 14C in an old, isolated sample of vegetation is 0.770 that expected from a present day sample with an equivalent carbon content. Calculate the age of the old sample in years.
The age of water samples or aqueous solutions can be determined by
determining the radioactive tritium. Calculate the age of the cognac sample that
had 10 times less radioactivity than the freshly prepared sample. The half-life of
tritium is 12.5 years.
Scientists can determine the age of ancient objects by the method of radiocarbon dating. The bombardment of the upper atmosphere by cosmic rays converts nitrogen to radioactive isotope of carbon, 14C, with
a half-life of about 5730 years. Vegetation absorbs carbon dioxide through the atmosphere and animal life assimilates 14C through food chains. When a plant or animal dies, it stops replacing its carbon and the
amount of ¹4C begins to decrease through radioactive decay. Therefore the level of radioactivity must also decay exponentially. A parchment fragment was discovered that had about 74% as much 14C
radioactivity as does plant material on earth today. Estimate the age of the parchment. (Round your answer to the nearest whole number.)
yr
Need Help? Watch It
Additional Materials
eBook
Chapter 18 Solutions
OWLv2 for Moore/Stanitski's Chemistry: The Molecular Science, 5th Edition, [Instant Access], 1 term (6 months)
Ch. 18.2 - Prob. 18.1PSPCh. 18.2 - Prob. 18.1ECh. 18.2 - Prob. 18.2PSPCh. 18.2 - Prob. 18.2ECh. 18.3 - Prob. 18.3PSPCh. 18.3 - Prob. 18.3ECh. 18.3 - Prob. 18.4CECh. 18.4 - Prob. 18.4PSPCh. 18.4 - Prob. 18.5ECh. 18.4 - Prob. 18.5PSP
Ch. 18.4 - Prob. 18.6PSPCh. 18.4 - Prob. 18.7PSPCh. 18.4 - Prob. 18.6ECh. 18.4 - Prob. 18.7CECh. 18.5 - Prob. 18.8ECh. 18.5 - Prob. 18.9CECh. 18.6 - Prob. 18.10ECh. 18.6 - Prob. 18.11ECh. 18.7 - Prob. 18.12ECh. 18.8 - Prob. 18.13ECh. 18.8 - Prob. 18.14ECh. 18.9 - Prob. 18.15ECh. 18 - Prob. 1SPCh. 18 - Prob. 2SPCh. 18 - Prob. 3SPCh. 18 - Prob. 4SPCh. 18 - Prob. 5SPCh. 18 - Prob. 1QRTCh. 18 - Prob. 2QRTCh. 18 - Prob. 3QRTCh. 18 - Prob. 4QRTCh. 18 - Prob. 5QRTCh. 18 - Prob. 6QRTCh. 18 - Prob. 7QRTCh. 18 - Prob. 8QRTCh. 18 - Prob. 9QRTCh. 18 - Complete the table.Ch. 18 - Prob. 11QRTCh. 18 - Prob. 12QRTCh. 18 - Prob. 13QRTCh. 18 - Prob. 14QRTCh. 18 - Prob. 15QRTCh. 18 - Prob. 16QRTCh. 18 - Prob. 17QRTCh. 18 - Prob. 18QRTCh. 18 - Prob. 19QRTCh. 18 - Prob. 20QRTCh. 18 - Prob. 21QRTCh. 18 - Prob. 22QRTCh. 18 - Prob. 23QRTCh. 18 - Prob. 24QRTCh. 18 - Prob. 25QRTCh. 18 - Prob. 26QRTCh. 18 - Prob. 27QRTCh. 18 - Prob. 28QRTCh. 18 - Prob. 29QRTCh. 18 - Prob. 30QRTCh. 18 - Prob. 31QRTCh. 18 - Prob. 32QRTCh. 18 - Prob. 33QRTCh. 18 - Prob. 34QRTCh. 18 - Prob. 35QRTCh. 18 - Prob. 36QRTCh. 18 - Prob. 37QRTCh. 18 - Prob. 38QRTCh. 18 - Prob. 39QRTCh. 18 - Prob. 40QRTCh. 18 - Prob. 41QRTCh. 18 - Prob. 42QRTCh. 18 - Prob. 43QRTCh. 18 - Prob. 44QRTCh. 18 - Prob. 45QRTCh. 18 - Prob. 46QRTCh. 18 - Prob. 47QRTCh. 18 - Prob. 48QRTCh. 18 - Prob. 49QRTCh. 18 - Prob. 50QRTCh. 18 - Prob. 51QRTCh. 18 - Prob. 52QRTCh. 18 - Prob. 53QRTCh. 18 - Prob. 54QRTCh. 18 - Prob. 55QRTCh. 18 - Prob. 56QRTCh. 18 - Prob. 57QRTCh. 18 - Prob. 58QRTCh. 18 - Prob. 59QRTCh. 18 - Prob. 60QRTCh. 18 - Prob. 61QRTCh. 18 - Prob. 62QRTCh. 18 - Prob. 63QRTCh. 18 - Prob. 64QRTCh. 18 - Prob. 65QRTCh. 18 - Prob. 66QRTCh. 18 - Prob. 67QRTCh. 18 - Prob. 68QRTCh. 18 - Prob. 69QRTCh. 18 - Prob. 70QRTCh. 18 - Prob. 71QRTCh. 18 - Prob. 72QRTCh. 18 - Prob. 73QRTCh. 18 - Prob. 74QRTCh. 18 - Prob. 75QRTCh. 18 - Prob. 76QRTCh. 18 - Prob. 77QRTCh. 18 - Prob. 78QRTCh. 18 - Prob. 79QRTCh. 18 - Prob. 80QRTCh. 18 - Prob. 81QRTCh. 18 - Prob. 82QRTCh. 18 - Prob. 83QRTCh. 18 - Prob. 84QRTCh. 18 - Prob. 85QRTCh. 18 - Prob. 86QRTCh. 18 - Prob. 87QRTCh. 18 - Prob. 88QRTCh. 18 - Prob. 89QRTCh. 18 - Prob. 91QRTCh. 18 - Prob. 92QRTCh. 18 - Prob. 93QRTCh. 18 - Prob. 94QRTCh. 18 - Prob. 95QRTCh. 18 - Prob. 96QRTCh. 18 - Prob. 18.ACPCh. 18 - Prob. 18.BCPCh. 18 - Prob. 18.CCPCh. 18 - Prob. 18.DCPCh. 18 - Prob. 18.ECP
Knowledge Booster
Similar questions
- Fluorine-18 is a radioactive isotope that decays by positron emission to form oxygen-18 with a half-life of 109.7 min. (A positron is a particle with the mass of an electron and a single unit of positive charge; the equation is F918O188+e+10 Physicians use 18F to study the brain by injecting a quantity of ?uoro-substituted glucose into the blood of a patient. The glucose accumulates in the regions where the brain is active and needs nourishment. (a) What is the rate constant for [lie decomposition of ?uorine-18? (b) If a sample of glucose containing radioactive fluorine-18 is injected into the blood, what percent of the radioactivity will remain after 5.59 h? (c) How long does it take for 99.99% of the 18F to decay?arrow_forwardCarbon-14 (C-14) with a half-life of 5730 years decays to nitrogen-14 (N-14). A sample of carbon dioxide containing carbon in the form of C-14 only is sealed in a vessel at 1.00-atmosphere pressure. Over time, the CO2 becomes NO2 through the radioactive decay process. The following equilibrium is established: 2NO2(g)N2O4(g) If the equilibrium constant for the equation as written is 1105 , what is the pressure of N2O4 after 20,000 years? Assume that the CO2 does not participate in any chemical reactions.arrow_forwardThe age of wine can be determined by measuring the trace amount of radioactive tritium, 3H, present in a sample. Tritium is formed from hydrogen in water vapor in the upper atmosphere by cosmic bombardment, so all naturally ocurring water contains a small amount of this isotope. Once the water is in a bottle of wine, however, the formation of additional tritium from the water is negligible, so the tritium initially present gradually diminishes by a first-order radioactive decay with a half-life of 12.5 years. If a bottle of wine is found to have a tritium concentration that is 0.184 that of freshly bottled wine (i.e. [3H]t = 0.184 [3H]0), what is the age of the wine?arrow_forward
- The age of wine can be determined by measuring the trace amount of radioactive tritium, ³H, present in a sample. Tritium is formed from hydrogen in water vapor in the upper atmosphere by cosmic bombardment, so all naturally ocurring water contains a small amount of this isotope. Once the water is in a bottle of wine, however, the formation of additional tritium from the water is negligible, so the tritium initially present gradually diminishes by a first-order radioactive decay with a half-life of 12.5 years. If a bottle of wine is found to have a tritium concentration that is 0.120 that of freshly bottled wine (i.e. [H]; = 0.120[³H]o), what is the age of the wine? i yearsarrow_forwardThe age of wine can be determined by measuring the trace amount of radioactive tritium, 3H, present in a sample. Tritium is formed from hydrogen in water vapor in the upper atmosphere by cosmic bombardment, so all naturally ocurring water contains a small amount of this isotope. Once the water is in a bottle of wine, however, the formation of additional tritium from the water is negligible, so the tritium initially present gradually diminishes by a first-order radioactive decay with a half-life of 12.5 years. If a bottle of wine is found to have a tritium concentration that is 0.191 that of freshly bottled wine (i.e. [³H]; = 0.191[°H]o), what is the age of the wine? i yearsarrow_forward. Let's apply the results of Problem 2 to potassium-argon dating frequently used to date sedimentary rocks. Potassium-40 decays by two different paths: electron emission electron capture where conversion to Ca occurs 89.1% of the time, and to Ar 10.9% of the time. The overall half-life for the decay of potassium-40 is 1.248 × 10⁹ years. Estimate the age of sedimentary rocks with an argon-40 to potassium-40 ratio of 1.02 %. 40 19K 140 Ca 40K 240 Ar 19 18-arrow_forward
- The half life for the radioactive decay of carbon-14 to nitrogen-14 is 5.73x 10^3 years. Suppose nuclear chemical analysis shows that there is 0.888 mmol of nitrogen-14 for every 1.000 mmol of carbon-14 in a certain sample of rock. Calculate the age of the rock. Round your answer to 2 significant digits.arrow_forwardRadon, one of the noble gases, is a decay product of uranium and is itself radioactive, with a half-life of 3.8 days3.8 days. As a heavy gas, radon can accumulate in low areas such as basements and crawl spaces. Consequently, radon is considered a significant source of air pollution and radiation exposure and, according to the EPA, is the second most frequent cause of lung cancer in the United States. Write the nuclear equation for the alpha decay of Rn‑222. nuclear equation:arrow_forwardThe vast majority (99.6%) of argon in Earth's atmosphere is 40Ar however the argon in the Sun is almost entirely 36Ar and 38Ar. The preponderance of 40Ar on Earth is attributed to its formation from 40K via beta emission. 40K has a long half-life of 1.27×109 years and makes up about 0.012% of the potassium on Earth. When molten rock cools, the argon accumulates in the rock. When a piece of rock is analyzed, it is found to contain 1.38 mmol of 40K and 1.15 mmol of 40Ar. How many billions of years ago did the rock form? Answers must be in billions of years and correct to +/- 0.2 billion years.arrow_forward
- 2. Can hydrogen peroxide be broken down by catalysts other than those found in living systems? Explain.arrow_forward4.arrow_forwardFor this question you will need to work all of your answers on scratch paper. Once completed, upload an image of your answers showing all work and dearly identifying your answers. Use the Browse My Computer button to upload an image. The following data was collected for the formation of N205. By reaction of NO2 and 0₂ 4NO2 02 2N₂Os Time in Mantes 10.0 20.0 30.0 40.0 50.0 60.0 70.0 10.0 90.0 100.0 [0₂] units of Molarity 0.0078 0.0077 0.0075 0.0072 0.0065 0.0063 0.0057 0.0048 0.0056 0.0021 0.0010 a. Show all your work, what is the average rate of the reaction? b. Show all your work, what is the instantaneous rate from 10.0 to 40.0 minutes? c. Show all your work, what is the instantaneous rate from 30.0 to 60.0 minutes? d. Show all your work, what is the instantaneous rate from 50.0 to 90.0 minutes?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning