Explanation Given: 1) Vector field F = 〈 − z 2 , 2 z x , 4 y − x 2 〉 . 2) Need to find equation of plane in following form a x + b y + c z = 0 where a , b , c are not all zero. 3) ∮ C F . d r = 0 for every closed surface C lying in the plane. Formula used: 1) Stoke’s theorem: If F is any continuously differentiable vector function and S is a surface enclosed by a curve C , then ∫ C F . d r = ∬ S ( ∇ × F ) . n d s Where n is the unit normal vector at any point of S 2) n = ∇ ϕ | ∇ ϕ | Where ϕ represents the plane ϕ having equation a x + b y + c x − d = 0 And | ∇ ϕ | = a 2 + b 2 + c 2 Calculation: F = 〈 y 2 , 2 z + x , 2 y 2 〉 [Given] Calculating ∇ × F and n which will be used in further calculation ∇ × F = | i ^ j ^ k ^ ∂ ∂ x ∂ ∂ y ∂ ∂ z y 2 2 z + x 2 y 2 | = i [ ∂ ∂ y ( 2 y 2 ) − ∂ ∂ z ( 2 z + x ) ] − j [ ∂ ∂ x ( 2 y 2 ) − ∂ ∂ z ( y 2 ) ] + k [ ∂ ∂ x ( 2 z + x ) − ∂ ∂ y ( y 2 ) ] = i [ 4 y − 2 ] − j [ 0 + 0 ] + k [ 1 − 2 y ] = [ 4 y − 2 ] i −

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Author: Rogawski

Publisher: MAC HIGHER

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Chapter 18.2, Problem 25E

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The plane for a given vector field using stokes’ theorem

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Chapter 18.2, Problem 24E

Chapter 18.2, Problem 26E

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Chapter 18 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

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The plane for a given vector field using stokes’ theorem

Solution Summary: The author explains how to determine the plane for a given vector field using stokes' theorem.

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Chapter 18 Solutions