Explanation Given information: The given line integral is ∮ C 5 y d x + 2 x d y , where C is the triangle with vertices ( − 1 , 0 ) , ( 1 , 0 ) and ( 0 , 1 ) . Orient the curve in counter clockwisedirection. Concept used: Green’s theorem : ∮ C P d x + Q d y = ∬ D ( ∂ Q ∂ x − ∂ P ∂ y ) d A Calculation: Since, ∮ C 5 y d x + 2 x d y (Given) Here, P = 5 y and Q = 2 x The region enclosed by 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1 − x . Using Green’s theorem, we have ∮ C P d x + Q d y = ∬ D ( ∂ Q ∂ x − ∂ P ∂ y ) d A ∮ C 5 y d x + 2 x d y = ∬ D ( ∂ ∂ x (

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Chapter 18.1, Problem 5E

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To calculate:The line integral ∮C5ydx+2xdy , where C is the triangle with vertices (−1,0),(1,0) and (0,1) using Green’s theorem.

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Chapter 18.1, Problem 4E

Chapter 18.1, Problem 6E

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Chapter 18 Solutions

CALCULUS 4E (LL) W/ ACHIEVE ACCESS

Ch. 18.1 - Prob. 1PQ Ch. 18.1 - Prob. 2PQ Ch. 18.1 - Prob. 3PQ Ch. 18.1 - Prob. 4PQ Ch. 18.1 - Prob. 5PQ Ch. 18.1 - Prob. 1E Ch. 18.1 - Prob. 2E Ch. 18.1 - Prob. 3E Ch. 18.1 - Prob. 4E Ch. 18.1 - Prob. 5E

Ch. 18.1 - Prob. 6E Ch. 18.1 - Prob. 7E Ch. 18.1 - Prob. 8E Ch. 18.1 - Prob. 9E Ch. 18.1 - Prob. 10E Ch. 18.1 - Prob. 11E Ch. 18.1 - Prob. 12E Ch. 18.1 - Prob. 13E Ch. 18.1 - Prob. 14E Ch. 18.1 - Prob. 15E Ch. 18.1 - Prob. 16E Ch. 18.1 - Prob. 17E Ch. 18.1 - Prob. 18E Ch. 18.1 - Prob. 19E Ch. 18.1 - Prob. 20E Ch. 18.1 - Prob. 21E Ch. 18.1 - Prob. 22E Ch. 18.1 - Prob. 23E Ch. 18.1 - Prob. 24E Ch. 18.1 - Prob. 25E Ch. 18.1 - Prob. 26E Ch. 18.1 - Prob. 27E Ch. 18.1 - Prob. 28E Ch. 18.1 - Prob. 29E Ch. 18.1 - Prob. 30E Ch. 18.1 - Prob. 31E Ch. 18.1 - Prob. 32E Ch. 18.1 - Prob. 33E Ch. 18.1 - Prob. 34E Ch. 18.1 - Prob. 35E Ch. 18.1 - Prob. 36E Ch. 18.1 - Prob. 37E Ch. 18.1 - Prob. 38E Ch. 18.1 - Prob. 39E Ch. 18.1 - Prob. 40E Ch. 18.1 - Prob. 41E Ch. 18.1 - Prob. 42E Ch. 18.1 - Prob. 43E Ch. 18.1 - Prob. 44E Ch. 18.1 - Prob. 45E Ch. 18.1 - Prob. 46E Ch. 18.1 - Prob. 47E Ch. 18.1 - Prob. 48E Ch. 18.1 - Prob. 49E Ch. 18.1 - Prob. 50E Ch. 18.1 - Prob. 51E Ch. 18.2 - Prob. 1PQ Ch. 18.2 - Prob. 2PQ Ch. 18.2 - Prob. 3PQ Ch. 18.2 - Prob. 4PQ Ch. 18.2 - Prob. 5PQ Ch. 18.2 - Prob. 1E Ch. 18.2 - Prob. 2E Ch. 18.2 - Prob. 3E Ch. 18.2 - Prob. 4E Ch. 18.2 - Prob. 5E Ch. 18.2 - Prob. 6E Ch. 18.2 - Prob. 7E Ch. 18.2 - Prob. 8E Ch. 18.2 - Prob. 9E Ch. 18.2 - Prob. 10E Ch. 18.2 - Prob. 11E Ch. 18.2 - Prob. 12E Ch. 18.2 - Prob. 13E Ch. 18.2 - Prob. 14E Ch. 18.2 - Prob. 15E Ch. 18.2 - Prob. 16E Ch. 18.2 - Prob. 17E Ch. 18.2 - Prob. 18E Ch. 18.2 - Prob. 19E Ch. 18.2 - Prob. 20E Ch. 18.2 - Prob. 21E Ch. 18.2 - Prob. 22E Ch. 18.2 - Prob. 23E Ch. 18.2 - Prob. 24E Ch. 18.2 - Prob. 25E Ch. 18.2 - Prob. 26E Ch. 18.2 - Prob. 27E Ch. 18.2 - Prob. 28E Ch. 18.2 - Prob. 29E Ch. 18.2 - Prob. 30E Ch. 18.2 - Prob. 31E Ch. 18.2 - Prob. 32E Ch. 18.2 - Prob. 33E Ch. 18.2 - Prob. 34E Ch. 18.2 - Prob. 35E Ch. 18.2 - Prob. 36E Ch. 18.2 - Prob. 37E Ch. 18.2 - Prob. 38E Ch. 18.3 - Prob. 1PQ Ch. 18.3 - Prob. 2PQ Ch. 18.3 - Prob. 3PQ Ch. 18.3 - Prob. 4PQ Ch. 18.3 - Prob. 5PQ Ch. 18.3 - Prob. 1E Ch. 18.3 - Prob. 2E Ch. 18.3 - Prob. 3E Ch. 18.3 - Prob. 4E Ch. 18.3 - Prob. 5E Ch. 18.3 - Prob. 6E Ch. 18.3 - Prob. 7E Ch. 18.3 - Prob. 8E Ch. 18.3 - Prob. 9E Ch. 18.3 - Prob. 10E Ch. 18.3 - Prob. 11E Ch. 18.3 - Prob. 12E Ch. 18.3 - Prob. 13E Ch. 18.3 - Prob. 14E Ch. 18.3 - Prob. 15E Ch. 18.3 - Prob. 16E Ch. 18.3 - Prob. 17E Ch. 18.3 - Prob. 18E Ch. 18.3 - Prob. 19E Ch. 18.3 - Prob. 20E Ch. 18.3 - Prob. 21E Ch. 18.3 - Prob. 22E Ch. 18.3 - Prob. 23E Ch. 18.3 - Prob. 24E Ch. 18.3 - Prob. 25E Ch. 18.3 - Prob. 26E Ch. 18.3 - Prob. 27E Ch. 18.3 - Prob. 28E Ch. 18.3 - Prob. 29E Ch. 18.3 - Prob. 30E Ch. 18.3 - Prob. 31E Ch. 18.3 - Prob. 32E Ch. 18.3 - Prob. 33E Ch. 18.3 - Prob. 34E Ch. 18.3 - Prob. 35E Ch. 18.3 - Prob. 36E Ch. 18.3 - Prob. 37E Ch. 18.3 - Prob. 38E Ch. 18.3 - Prob. 39E Ch. 18.3 - Prob. 40E Ch. 18.3 - Prob. 41E Ch. 18.3 - Prob. 42E Ch. 18.3 - Prob. 43E Ch. 18.3 - Prob. 44E Ch. 18 - Prob. 1CRE Ch. 18 - Prob. 2CRE Ch. 18 - Prob. 3CRE Ch. 18 - Prob. 4CRE Ch. 18 - Prob. 5CRE Ch. 18 - Prob. 6CRE Ch. 18 - Prob. 7CRE Ch. 18 - Prob. 8CRE Ch. 18 - Prob. 9CRE Ch. 18 - Prob. 10CRE Ch. 18 - Prob. 11CRE Ch. 18 - Prob. 12CRE Ch. 18 - Prob. 13CRE Ch. 18 - Prob. 14CRE Ch. 18 - Prob. 15CRE Ch. 18 - Prob. 16CRE Ch. 18 - Prob. 17CRE Ch. 18 - Prob. 18CRE Ch. 18 - Prob. 19CRE Ch. 18 - Prob. 20CRE Ch. 18 - Prob. 21CRE Ch. 18 - Prob. 22CRE Ch. 18 - Prob. 23CRE Ch. 18 - Prob. 24CRE Ch. 18 - Prob. 25CRE Ch. 18 - Prob. 26CRE Ch. 18 - Prob. 27CRE Ch. 18 - Prob. 28CRE Ch. 18 - Prob. 29CRE Ch. 18 - Prob. 30CRE Ch. 18 - Prob. 31CRE Ch. 18 - Prob. 32CRE Ch. 18 - Prob. 33CRE Ch. 18 - Prob. 34CRE Ch. 18 - Prob. 35CRE Ch. 18 - Prob. 36CRE Ch. 18 - Prob. 37CRE Ch. 18 - Prob. 38CRE Ch. 18 - Prob. 39CRE Ch. 18 - Prob. 40CRE Ch. 18 - Prob. 41CRE

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The line integral ∮ C 5 y d x + 2 x d y , where C is the triangle with vertices ( − 1 , 0 ) , ( 1 , 0 ) and ( 0 , 1 ) using Green’s theorem.

Solution Summary: The author explains how to calculate the line integral displaystyleundersetCoint5ydx+2xdy using Green’s theorem.

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To calculate:The line integral ∮C5ydx+2xdy , where C is the triangle with vertices (−1,0),(1,0) and (0,1) using Green’s theorem.

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Chapter 18 Solutions