It should be explained that whether the sign of entropy change for system, surroundings and universe is greater than zero or not. Concept introduction: The universe consists of two parts, systems and surroundings. The entropy change for the universe is the sum of entropy change for the system and for surroundings. ΔS o ( universe ) = ΔS o ( system ) +ΔS o ( surroundings ) The ΔS o ( universe ) should be greater than zero for a spontaneous process. The ΔS o ( system ) can be calculated by the following expression, ΔS o ( system ) = Δ r S ° = ∑ nS ° ( products ) - ∑ nS ° ( reactants ) The ΔS o ( surroundings ) can be calculated by the following expression, ΔS o ( surroundings ) = - Δ r H o T Here, Δ r H ° is the enthalpy change for the reaction. The Gibbs free energy or the free energy change is a thermodynamic quantity represented by ΔG o . It is related to entropy and entropy by the following expression, Δ r G o =Δ r H o -TΔ r S o ΔG o is also related to the equilibrium constant K by the equation, Δ r G o = -RTlnK p The rearranged expression is, K p = e - Δ r G o RT
It should be explained that whether the sign of entropy change for system, surroundings and universe is greater than zero or not. Concept introduction: The universe consists of two parts, systems and surroundings. The entropy change for the universe is the sum of entropy change for the system and for surroundings. ΔS o ( universe ) = ΔS o ( system ) +ΔS o ( surroundings ) The ΔS o ( universe ) should be greater than zero for a spontaneous process. The ΔS o ( system ) can be calculated by the following expression, ΔS o ( system ) = Δ r S ° = ∑ nS ° ( products ) - ∑ nS ° ( reactants ) The ΔS o ( surroundings ) can be calculated by the following expression, ΔS o ( surroundings ) = - Δ r H o T Here, Δ r H ° is the enthalpy change for the reaction. The Gibbs free energy or the free energy change is a thermodynamic quantity represented by ΔG o . It is related to entropy and entropy by the following expression, Δ r G o =Δ r H o -TΔ r S o ΔG o is also related to the equilibrium constant K by the equation, Δ r G o = -RTlnK p The rearranged expression is, K p = e - Δ r G o RT
Solution Summary: The author explains that the sign of entropy change for system, surroundings and universe is greater than zero or not.
It should be explained that whether the sign of entropy change for system, surroundings and universe is greater than zero or not.
Concept introduction:
The universe consists of two parts, systems and surroundings. The entropy change for the universe is the sum of entropy change for the system and for surroundings.
ΔSo(universe)= ΔSo(system)+ΔSo(surroundings)
The ΔSo(universe) should be greater than zero for a spontaneous process.
The ΔSo(system) can be calculated by the following expression,
ΔSo(system)= ΔrS°= ∑nS°(products)-∑nS°(reactants)
The ΔSo(surroundings) can be calculated by the following expression,
ΔSo(surroundings)=- ΔrHoT
Here, ΔrH° is the enthalpy change for the reaction.
The Gibbs free energy or the free energy change is a thermodynamic quantity represented by ΔGo. It is related to entropy and entropy by the following expression,
ΔrGo=ΔrHo-TΔrSo
ΔGo is also related to the equilibrium constant K by the equation,
ΔrGo= -RTlnKp
The rearranged expression is,
Kp= e- ΔrGoRT
(b)
Interpretation Introduction
Interpretation:
The sign of ΔrH° and ΔrGo value for the given reaction should be predicted.
Concept introduction:
The universe consists of two parts, systems and surroundings. The entropy change for the universe is the sum of entropy change for the system and for surroundings.
ΔSo(universe)= ΔSo(system)+ΔSo(surroundings)
The ΔSo(universe) should be greater than zero for a spontaneous process.
The ΔSo(system) can be calculated by the following expression,
ΔSo(system)= ΔrS°= ∑nS°(products)-∑nS°(reactants)
The ΔSo(surroundings) can be calculated by the following expression,
ΔSo(surroundings)=- ΔrHoT
Here, ΔrH° is the enthalpy change for the reaction.
The Gibbs free energy or the free energy change is a thermodynamic quantity represented by ΔGo. It is related to entropy and entropy by the following expression,
ΔrGo=ΔrHo-TΔrSo
ΔGo is also related to the equilibrium constant K by the equation,
ΔrGo= -RTlnKp
The rearranged expression is,
Kp= e- ΔrGoRT
(c)
Interpretation Introduction
Interpretation:
It should be identified that whether the value of Kp is very large, very small or nearer to 1 also that the equilibrium constant will be larger or smaller for temperatures greater than 298K.
Concept introduction:
The universe consists of two parts, systems and surroundings. The entropy change for the universe is the sum of entropy change for the system and for surroundings.
ΔSo(universe)= ΔSo(system)+ΔSo(surroundings)
The ΔSo(universe) should be greater than zero for a spontaneous process.
The ΔSo(system) can be calculated by the following expression,
ΔSo(system)= ΔrS°= ∑nS°(products)-∑nS°(reactants)
The ΔSo(surroundings) can be calculated by the following expression,
ΔSo(surroundings)=- ΔrHoT
Here, ΔrH° is the enthalpy change for the reaction.
The Gibbs free energy or the free energy change is a thermodynamic quantity represented by ΔGo. It is related to entropy and entropy by the following expression,
ΔrGo=ΔrHo-TΔrSo
ΔGo is also related to the equilibrium constant K by the equation,
Relative Intensity
Part VI. consider the multi-step reaction below for compounds A, B, and C.
These compounds were subjected to mass spectrometric analysis and
the following spectra for A, B, and C was obtained.
Draw the structure of B and C and match all three compounds
to the correct spectra.
Relative Intensity
Relative Intensity
20
NaоH
0103
Br
(B)
H2504
→ (c)
(A)
100-
MS-NU-0547
80
40
20
31
10
20
100-
MS2016-05353CM
80
60
100
MS-NJ-09-3
80
60
40
20
45
J.L
80
S1
84
M+
absent
राग
135 137
S2
62
164 166
11
S3
25
50
75
100
125
150
175
m/z
Don't used hand raiting and don't used Ai solution
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The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY