
Concept explainers
(a)
Interpretation:
The relative charge on the
Concept introduction:
Heavy atoms have unstable nuclei. Due to which they are radioactive and disintegrate into smaller nuclei. The decay of radioactive nuclei can be done by alpha particle emission, beta-particle emission, positron decay, gamma decay, and electron capture.

Answer to Problem 8E
The charge on alpha particle is
Explanation of Solution
Alpha particle is similar to the helium nucleus
The charge on alpha particle is stated above.
(b)
Interpretation:
The relative charge on the
Concept introduction:
Heavy atoms have unstable nuclei. Due to which they are radioactive and disintegrates into smaller nuclei. The decay of radioactive nuclei can be done by alpha particle emission, beta-particle emission, positron decay, gamma decay, and electron capture.

Answer to Problem 8E
The charge on beta particle is
Explanation of Solution
A beta particle is similar to an electron
The charge on
(c)
Interpretation:
The relative charge on the
Concept introduction:
Heavy atoms have unstable nuclei. Due to which they are radioactive and disintegrates into smaller nuclei. The decay of radioactive nuclei can be done by alpha particle emission, beta-particle emission, positron decay, gamma decay, and electron capture.

Answer to Problem 8E
The charge on gamma particle is
Explanation of Solution
Gamma ray is powerful radioactive radiation which has zero mass and zero charge. The symbol used to represent the gamma ray is
The charge on
(d)
Interpretation:
The relative charge on the
Concept introduction:
Heavy atoms have unstable nuclei. Due to which they are radioactive and disintegrates into smaller nuclei. The decay of radioactive nuclei can be done by alpha particle emission, beta-particle emission, positron decay, gamma decay, and electron capture.

Answer to Problem 8E
The charge on positron
Explanation of Solution
Positron is the opposite of electrons on the basis of charge. The mass on positron is zero but it contains one positive charge. The symbol used to represent positron is
The charge on
(e)
Interpretation:
The relative charge on the
Concept introduction:
Heavy atoms have unstable nuclei. Due to which they are radioactive and disintegrates into smaller nuclei. The decay of radioactive nuclei can be done by alpha particle emission, beta-particle emission, positron decay, gamma decay, and electron capture.

Answer to Problem 8E
The charge on neutron
Explanation of Solution
Neutrons are similar to protons on the basis of charge. The charge on neutron is zero but the mass of neutron is approximately
The charge on neutron is
(f)
Interpretation:
The relative charge on the proton
Concept introduction:
Heavy atoms have unstable nuclei. Due to which they are radioactive and disintegrates into smaller nuclei. The decay of radioactive nuclei can be done by alpha particle emission, beta-particle emission, positron decay, gamma decay, and electron capture.

Answer to Problem 8E
The charge on proton
Explanation of Solution
Protons are the particles which have mass equal to
The charge on proton is
Want to see more full solutions like this?
Chapter 18 Solutions
EBK INTRODUCTORY CHEMISTRY
- For Raman spectroscopy/imaging, which statement is not true regarding its disadvantages? a) Limited spatial resolution. b) Short integration time. c) A one-dimensional technique. d) Weak signal, only 1 in 108 incident photons is Raman scattered. e) Fluorescence interference.arrow_forwardUsing a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c. (Please provide a full derivation of the equation for x from the equation for I). d) Calculate x for the 1645 cm-1 bandarrow_forwardI need help with the follloaingarrow_forward
- For a CARS experiment on a Raman band 918 cm-1, if omega1= 1280 nm, calculate the omega2 in wavelength (nm) and the CARS output in wavelength (nm).arrow_forwardI need help with the following questionarrow_forwardFor CARS, which statement is not true regarding its advantages? a) Contrast signal based on vibrational characteristics, no need for fluorescent tagging. b) Stronger signals than spontaneous Raman. c) Suffers from fluorescence interference, because CARS signal is at high frequency. d) Faster, more efficient imaging for real-time analysis. e) Higher resolution than spontaneous Raman microscopy.arrow_forward
- Draw the major product of the Claisen condensation reaction between two molecules of this ester. Ignore inorganic byproducts. Incorrect, 5 attempts remaining 1. NaOCH3/CH3OH 2. Acidic workup Select to Draw O Incorrect, 5 attempts remaining The total number of carbons in the parent chain is incorrect. Review the reaction conditions including starting materials and/or intermediate structures and recount the number of carbon atoms in the parent chain of your structure. OKarrow_forwardUsing a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40. a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L) b) Calculate the molar absorptivity, a, of the 1645 cm-1 band c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c d) Calculate x for the 1645 cm-1 bandarrow_forwardConvert 1.38 eV into wavelength (nm) and wavenumber (cm-1) (c = 2.998 x 108 m/s; h = 6.626 x 10-34 J*s).arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
- Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub CoPrinciples of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage Learning



