Concept explainers
(a)
The current though each bulb.
(a)
Answer to Problem 79GP
The current in a lightbulb A is
The current in a lightbulb B is
Explanation of Solution
Given:
Power lightbulb A,
Voltage of lightbulb A,
Power lightbulb B,
Voltage of lightbulb B,
Formula used:
Where,
Calculation:
Rearrange the formula of power,
According to the question, current in a lightbulb A:
According to the question, current in a lightbulb B:
Conclusion: The current in a lightbulb A is
(b)
The resistance though each bulb.
(b)
Answer to Problem 79GP
The resistance in a lightbulb A is
The resistance in a lightbulb B is
Explanation of Solution
Given:
Power lightbulb A,
Voltage of lightbulb A,
Power lightbulb B,
Voltage of lightbulb B,
Formula used:
Power
Where,
Also,
Where,
Calculation:
Rearrange the formula,
According to the question, resistance in a lightbulb A:
According to the question, resistance in a lightbulb B:
Conclusion: The resistance in a lightbulb A is
(c)
The amount of chargethat passes in one hour.
(c)
Answer to Problem 79GP
The charge in the lightbulb A is
The charge in a lightbulb B is
Explanation of Solution
Given:
Power lightbulb A,
Voltage of lightbulb A,
Power lightbulb B,
Voltage of lightbulb B,
Current in lightbulb A,
Current in lightbulb B,
Temperature change,
Formula used:
Current:
Where,
Q is the amount of charge and
Calculation:
Rearrange the formula,
According to the question, amount of charge that passes in the lightbulb A:
Substitute the given values:
According to the question, amount of charge that passesin the lightbulb B:
Substitute the given values:
Conclusion: The charge that passesin lightbulb A is
(d)
The energy each bulb uses in one hour should be determined.
(d)
Answer to Problem 79GP
The answer is
Explanation of Solution
Given:
Power lightbulb A,
Voltage of lightbulb A,
Power lightbulb B,
Voltage of lightbulb B,
Current in lightbulb A,
Current in lightbulb B,
Temperature change,
Formula used:
The power consumed by the light:
Where,
Calculation:
Rearrange the formula,
According to the question, two light bulbs are having the same power. So,
Substitute the given values:
Conclusion: The energy is
(e)
The bulb that requires larger diameter wires to connect its power source and the bulb.
(e)
Answer to Problem 79GP
The diameter of wire B must be as larger because it has much resistance.
Explanation of Solution
Given:
Power lightbulb A,
Voltage of lightbulb A,
Power lightbulb B,
Voltage of lightbulb B,
Current in lightbulb A,
Current in lightbulb B,
Temperature change,
The resistance in a lightbulb A is
The resistance in a lightbulb B is
Formula used:
It is known that resistance:
Where,
Calculation:
According to the given formula,
Since wire B has much resistance, its diameter must be as larger as possible.
Conclusion: The wire B has much resistance.
Chapter 18 Solutions
Physics: Principles with Applications
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