Chapter 18, Problem 2P

To determine

The charge passes through the battery, using a current of $\text{6}\text{.7}\text{A}$ for $\text{5}\text{h}$ .

Answer to Problem 2P

The charge passes through the battery: $\text{ 1}\text{.2}\times {\text{10}}^{\text{5}}\text{C}$

Explanation of Solution

Given info:

Current, $\text{I}\text{=}\text{6}\text{.7}\text{A}$

Charge of electron, $\text{e=}\text{1}{\text{.6×10}}^{\text{-19}}\text{C}$

Time, $\text{t}\text{= 5}\text{h}\text{= 5}\text{.0}\times \text{60}\times \text{60}\text{s}$

Formula used:

The current is given by

  $\text{I}\text{=}\frac{\Delta \text{Q}}{\Delta \text{t}}$

For the calculation of charge, $\Delta \text{Q}\text{=}\text{I}\Delta \text{t}$

Where, $I=$ current, $\Delta Q=$ amount of charge (change), and $\Delta t=$ change in time.

Calculation:

Substituting the given values in formula, $\Delta \text{Q}\text{=}\text{I}\Delta \text{t}$

  $\text{ = 6}\text{.7}\times \text{5}\times \text{60}\times \text{60}$

  $\text{= 1}\text{.2}\times {\text{10}}^{\text{5}}\text{C}$

Conclusion:

The charge passes through battery: $\text{1}\text{.2}\times {\text{10}}^{\text{5}}\text{C}$