Chemistry: The Central Science Plus Mastering Chemistry with Pearson eText -- Access Card Package (14th Edition)
14th Edition
ISBN: 9780134292816
Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Matthew E. Stoltzfus
Publisher: PEARSON
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Chapter 18, Problem 63AE
Interpretation Introduction
To determine: The process by which
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For Raman spectroscopy/imaging, which statement is not true regarding its disadvantages?
a) Limited spatial resolution.
b) Short integration time.
c) A one-dimensional technique.
d) Weak signal, only 1 in 108 incident photons is Raman scattered.
e) Fluorescence interference.
Using a cell of known pathlength b = 1.25115 x 10-3 cm, a water absorption spectrum was measured. The band at 1645 cm-1, assigned to the O-H bending, showed an absorbance, A, of 1.40.
a) Assuming that water density is 1.00 g/mL, calculate the water molar concentration c (hint: M= mole/L)
b) Calculate the molar absorptivity, a, of the 1645 cm-1 band
c) The transmitted light, I, can be written as I= Ioexp(-xb), where x is the absorption coefficient (sometimes designated as alpha), Io is the input light, and b is the cell pathlength. Prove that x= (ln10)*x*c. (Please provide a full derivation of the equation for x from the equation for I).
d) Calculate x for the 1645 cm-1 band
I need help with the follloaing
Chapter 18 Solutions
Chemistry: The Central Science Plus Mastering Chemistry with Pearson eText -- Access Card Package (14th Edition)
Ch. 18.1 - Prob. 18.1.1PECh. 18.1 - Prob. 18.1.2PECh. 18.1 - Prob. 18.2.1PECh. 18.1 - Practice Exercise 2 The bond energy in N2 is 941...Ch. 18.2 - Prob. 18.3.1PECh. 18.2 - Prob. 18.3.2PECh. 18 - Prob. 1DECh. 18 - Prob. 1ECh. 18 - Prob. 2ECh. 18 - The figure shows the three lowest regions of...
Ch. 18 - Prob. 4ECh. 18 - Where does the energy come from to evaporate the...Ch. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - The first stage of treatment at the reverse...Ch. 18 - Prob. 9ECh. 18 - Prob. 10ECh. 18 - Prob. 11ECh. 18 - How are the boundaries between the regions of the...Ch. 18 - Air pollution in the Mexico City metropolitan area...Ch. 18 - Prob. 14ECh. 18 - Prob. 15ECh. 18 - Prob. 16ECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Distinguish between photodissociation and...Ch. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Do the reactions involved in ozone depletion...Ch. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Alcohol-based fuels for automobiles lead to the...Ch. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36ECh. 18 - Prob. 37ECh. 18 - Prob. 38ECh. 18 - Prob. 39ECh. 18 - Prob. 40ECh. 18 - Prob. 41ECh. 18 - Prob. 42ECh. 18 - Although there are many ions in seawater, the...Ch. 18 - The Ogallala aquifer described in the Close Look...Ch. 18 - Prob. 45ECh. 18 - Prob. 46ECh. 18 - List the common products formed when an organic...Ch. 18 - Prob. 48ECh. 18 - Prob. 49ECh. 18 - Prob. 50ECh. 18 - Prob. 51ECh. 18 - Prob. 52ECh. 18 - Prob. 53ECh. 18 - Prob. 54ECh. 18 - Prob. 55ECh. 18 - Prob. 56ECh. 18 - Prob. 57ECh. 18 - Prob. 58ECh. 18 - Prob. 59ECh. 18 - Prob. 60ECh. 18 - Prob. 61AECh. 18 - Prob. 62AECh. 18 - Prob. 63AECh. 18 - Prob. 64AECh. 18 - Prob. 65AECh. 18 - Prob. 66AECh. 18 - Prob. 67AECh. 18 - Explain, using Le Châtelier’s principle, why the...Ch. 18 - Prob. 69AECh. 18 - Prob. 70AECh. 18 - Prob. 71AECh. 18 - Prob. 72AECh. 18 - Prob. 73AECh. 18 - Prob. 74AECh. 18 - Prob. 75AECh. 18 - Prob. 76AECh. 18 - Prob. 77AECh. 18 - Prob. 78IECh. 18 - Prob. 79IECh. 18 - Prob. 80IECh. 18 - Prob. 81IECh. 18 - Prob. 82IECh. 18 - Prob. 83IECh. 18 - Prob. 84IECh. 18 - 18.85 The main reason that distillation is a...Ch. 18 - Prob. 86IECh. 18 - Prob. 87IECh. 18 - Prob. 88IECh. 18 - Prob. 89IECh. 18 - Prob. 90IECh. 18 - Prob. 91IECh. 18 - Prob. 92IE
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- For a CARS experiment on a Raman band 918 cm-1, if omega1= 1280 nm, calculate the omega2 in wavelength (nm) and the CARS output in wavelength (nm).arrow_forwardI need help with the following questionarrow_forwardFor CARS, which statement is not true regarding its advantages? a) Contrast signal based on vibrational characteristics, no need for fluorescent tagging. b) Stronger signals than spontaneous Raman. c) Suffers from fluorescence interference, because CARS signal is at high frequency. d) Faster, more efficient imaging for real-time analysis. e) Higher resolution than spontaneous Raman microscopy.arrow_forward
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