The affect on the equilibrium of the reaction, CuO ( s ) + H 2 ( g ) ⇌ Cu ( l ) + H 2 ( g ) when the volume of the system is reduced to 1 10 of the original volume is to be predicted. Concept introduction: Equilibrium is the state where the concentration of the reactant is equal to the concentration of the product. According to Le Chatelier’s Principle, the equilibrium shifts in such a way or a direction that it can reduce the effect of change.

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Answer 1

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Chapter 18, Problem 5PE

Interpretation Introduction

Interpretation:

The affect on the equilibrium of the reaction, CuO(s)+H2(g)⇌Cu(l)+H2(g) when the volume of the system is reduced to 110 of the original volume is to be predicted.

Concept introduction:

Equilibrium is the state where the concentration of the reactant is equal to the concentration of the product. According to Le Chatelier’s Principle, the equilibrium shifts in such a way or a direction that it can reduce the effect of change.

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Answer 2

Question

Chapter 18, Problem 5PE

Interpretation Introduction

Interpretation:

The affect on the equilibrium of the reaction, CuO(s)+H2(g)⇌Cu(l)+H2(g) when the volume of the system is reduced to 110 of the original volume is to be predicted.

Concept introduction:

Equilibrium is the state where the concentration of the reactant is equal to the concentration of the product. According to Le Chatelier’s Principle, the equilibrium shifts in such a way or a direction that it can reduce the effect of change.

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Answer 3

Question

Chapter 18, Problem 5PE

Interpretation Introduction

Interpretation:

The affect on the equilibrium of the reaction, CuO(s)+H2(g)⇌Cu(l)+H2(g) when the volume of the system is reduced to 110 of the original volume is to be predicted.

Concept introduction:

Equilibrium is the state where the concentration of the reactant is equal to the concentration of the product. According to Le Chatelier’s Principle, the equilibrium shifts in such a way or a direction that it can reduce the effect of change.

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Answer 4

Question

Chapter 18, Problem 5PE

Interpretation Introduction

Interpretation:

The affect on the equilibrium of the reaction, CuO(s)+H2(g)⇌Cu(l)+H2(g) when the volume of the system is reduced to 110 of the original volume is to be predicted.

Concept introduction:

Equilibrium is the state where the concentration of the reactant is equal to the concentration of the product. According to Le Chatelier’s Principle, the equilibrium shifts in such a way or a direction that it can reduce the effect of change.

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Answer 5

Chapter 18, Problem 5PE

Interpretation Introduction

Interpretation:

The affect on the equilibrium of the reaction, CuO(s)+H2(g)⇌Cu(l)+H2(g) when the volume of the system is reduced to 110 of the original volume is to be predicted.

Concept introduction:

Equilibrium is the state where the concentration of the reactant is equal to the concentration of the product. According to Le Chatelier’s Principle, the equilibrium shifts in such a way or a direction that it can reduce the effect of change.

Answer 6

Chapter 18, Problem 5PE

Interpretation Introduction

Interpretation:

The affect on the equilibrium of the reaction, CuO(s)+H2(g)⇌Cu(l)+H2(g) when the volume of the system is reduced to 110 of the original volume is to be predicted.

Concept introduction:

Equilibrium is the state where the concentration of the reactant is equal to the concentration of the product. According to Le Chatelier’s Principle, the equilibrium shifts in such a way or a direction that it can reduce the effect of change.

Answer 7

Chapter 18, Problem 5PE

Interpretation Introduction

Interpretation:

The affect on the equilibrium of the reaction, CuO(s)+H2(g)⇌Cu(l)+H2(g) when the volume of the system is reduced to 110 of the original volume is to be predicted.

Concept introduction:

Equilibrium is the state where the concentration of the reactant is equal to the concentration of the product. According to Le Chatelier’s Principle, the equilibrium shifts in such a way or a direction that it can reduce the effect of change.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 18 - Prob. 1E Ch. 18 - Prob. 2E Ch. 18 - Prob. 3E Ch. 18 - Prob. 4E Ch. 18 - Prob. 5E Ch. 18 - Prob. 6E Ch. 18 - Prob. 7E Ch. 18 - Prob. 8E Ch. 18 - Prob. 9E Ch. 18 - Prob. 10E

Solution Summary: The author explains that equilibrium is not affected, as one mole of gas is present on both sides of reaction.

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