MAST F/ CHEM: THE CENTRAL SCI CODE ALON
14th Edition
ISBN: 9781323654378
Author: Brown
Publisher: PEARSON
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Chapter 18, Problem 55E
Interpretation Introduction
To determine: The ways in which using the principle, “it is better to use as few steps as possible in making a new chemical” advances the goals of green chemistry and relation between this principle and energy efficiency.
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Please help me with # 4 and 5. Thanks in advance!
A small artisanal cheesemaker is testing the acidity of their milk
before it coagulates. During fermentation, bacteria produce lactic
acid (K₁ = 1.4 x 104), a weak acid that helps to curdle the milk and
develop flavor. The cheesemaker has measured that the developing
mixture contains lactic acid at an initial concentration of 0.025 M.
Your task is to calculate the pH of this mixture and determine whether
it meets the required acidity for proper cheese development. To
achieve the best flavor, texture and reduce/control microbial growth,
the pH range needs to be between pH 4.6 and 5.0.
Assumptions:
Lactic acid is a monoprotic acid
H
H
:0:0:
H-C-C
H
:0:
O-H
Figure 1: Lewis Structure for Lactic Acid
For simplicity, you can use the generic formula HA to represent the acid
You can assume lactic acid dissociation is in water as milk is mostly water.
Temperature is 25°C
1. Write the K, expression for the dissociation of lactic acid in the space provided. Do not forget to
include state symbols.…
Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product
structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s).
Be sure to account for all bond-breaking and bond-making steps.
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H.
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:0:
:6:
S:
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Select to Edit Arrows
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Select to Edit Arrows
H
:0:
H
:CI:
Rotation
Select to Edit Arrows
H.
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:0:
:0:
:0:
S:
Chapter 18 Solutions
MAST F/ CHEM: THE CENTRAL SCI CODE ALON
Ch. 18.1 - Prob. 18.1.1PECh. 18.1 - Prob. 18.1.2PECh. 18.1 - Prob. 18.2.1PECh. 18.1 - Practice Exercise 2 The bond energy in N2 is 941...Ch. 18.2 - Prob. 18.3.1PECh. 18.2 - Prob. 18.3.2PECh. 18 - Prob. 1DECh. 18 - Prob. 1ECh. 18 - Prob. 2ECh. 18 - The figure shows the three lowest regions of...
Ch. 18 - Prob. 4ECh. 18 - Where does the energy come from to evaporate the...Ch. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - The first stage of treatment at the reverse...Ch. 18 - Prob. 9ECh. 18 - Prob. 10ECh. 18 - Prob. 11ECh. 18 - How are the boundaries between the regions of the...Ch. 18 - Air pollution in the Mexico City metropolitan area...Ch. 18 - Prob. 14ECh. 18 - Prob. 15ECh. 18 - Prob. 16ECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Distinguish between photodissociation and...Ch. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Do the reactions involved in ozone depletion...Ch. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Alcohol-based fuels for automobiles lead to the...Ch. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36ECh. 18 - Prob. 37ECh. 18 - Prob. 38ECh. 18 - Prob. 39ECh. 18 - Prob. 40ECh. 18 - Prob. 41ECh. 18 - Prob. 42ECh. 18 - Although there are many ions in seawater, the...Ch. 18 - The Ogallala aquifer described in the Close Look...Ch. 18 - Prob. 45ECh. 18 - Prob. 46ECh. 18 - List the common products formed when an organic...Ch. 18 - Prob. 48ECh. 18 - Prob. 49ECh. 18 - Prob. 50ECh. 18 - Prob. 51ECh. 18 - Prob. 52ECh. 18 - Prob. 53ECh. 18 - Prob. 54ECh. 18 - Prob. 55ECh. 18 - Prob. 56ECh. 18 - Prob. 57ECh. 18 - Prob. 58ECh. 18 - Prob. 59ECh. 18 - Prob. 60ECh. 18 - Prob. 61AECh. 18 - Prob. 62AECh. 18 - Prob. 63AECh. 18 - Prob. 64AECh. 18 - Prob. 65AECh. 18 - Prob. 66AECh. 18 - Prob. 67AECh. 18 - Explain, using Le Châtelier’s principle, why the...Ch. 18 - Prob. 69AECh. 18 - Prob. 70AECh. 18 - Prob. 71AECh. 18 - Prob. 72AECh. 18 - Prob. 73AECh. 18 - Prob. 74AECh. 18 - Prob. 75AECh. 18 - Prob. 76AECh. 18 - Prob. 77AECh. 18 - Prob. 78IECh. 18 - Prob. 79IECh. 18 - Prob. 80IECh. 18 - Prob. 81IECh. 18 - Prob. 82IECh. 18 - Prob. 83IECh. 18 - Prob. 84IECh. 18 - 18.85 The main reason that distillation is a...Ch. 18 - Prob. 86IECh. 18 - Prob. 87IECh. 18 - Prob. 88IECh. 18 - Prob. 89IECh. 18 - Prob. 90IECh. 18 - Prob. 91IECh. 18 - Prob. 92IE
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- 3:48 PM Fri Apr 4 K Problem 4 of 10 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Mg. :0: Select to Add Arrows :0: :Br: Mg :0: :0: Select to Add Arrows Mg. Br: :0: 0:0- Br -190 H 0:0 Select to Add Arrows Select to Add Arrows neutralizing workup H CH3arrow_forwardIarrow_forwardDraw the Markovnikov product of the hydrobromination of this alkene. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for this problem. + Explanation Check 1 X E 4 1 1 1 1 1 HBr Click and drag to start drawing a structure. 80 LE #3 @ 2 $4 0 I அ2 % 85 F * K M ? BH 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center & 6 27 FG F10 8 9 R T Y U D F G H P J K L Z X C V B N M Q W A S H option command H command optiarrow_forward
- Be sure to use wedge and dash bonds to show the stereochemistry of the products when it's important, for example to distinguish between two different major products. Predict the major products of the following reaction. Explanation Q F1 A Check F2 @ 2 # 3 + X 80 F3 W E S D $ 4 I O H. H₂ 2 R Pt % 05 LL ee F6 F5 T <6 G Click and drag to start drawing a structure. 27 & A 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Acce Y U H DII 8 9 F10 4 J K L Z X C V B N M T H option command F11 P H commandarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the intermediate and product in this reaction or mechanistic step(s). Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore inorganic byproducts. H :0: CH3 O: OH Q CH3OH2+ Draw Intermediate protonation CH3OH CH3OH nucleophilic addition H Draw Intermediate deprotonation :0: H3C CH3OH2* protonation H 0: H CH3 H.arrow_forwardPredicting the reactants or products of hemiacetal and acetal formation uentify the missing organic reactants in the following reaction: H+ X+Y OH H+ за Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H2O) are not shown. In the drawing area below, draw the skeletal ("line") structures of the missing organic reactants X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Explanation Check Click and drag to start drawing a structure. ? olo 18 Ar © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forward
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