Explanation It is given thatthe value V of a precious stone varies directly as the square of its weight w. The equation for the above direct proportion is given by, V = k w 2 ... ( 1 ) Let w 0 be the original weight of the stone hence the above relation is rewritten as, 27 , 000 = k w 0 2 Let w 1 , w 2 be the weights of smaller and larger pieces of the stone and they are divided in the ratio of 2 to 1. Thus the original weight is rewritten as follows. w 0 = w 1 + w 2 w 0 = w 1 + 2 w 1 ( ∵ w 1 w 2 = 2 1 ) w 0 = 3 w 1 The weights w 1 and w 2 are rewritten in terms of w 0 as follows

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

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ISBN: 9780137554843

Author: Allyn Washington, Richard Evans

Publisher: PEARSON+

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Chapter 18, Problem 50RE

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The loss in value of a precious stone.

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Chapter 18, Problem 49RE

Chapter 18, Problem 51RE

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Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

Ch. 18.1 - Practice Exercise In a certain electric field a...Ch. 18.1 - Prob. 2PE Ch. 18.1 - Prob. 1E Ch. 18.1 - Prob. 2E Ch. 18.1 - Prob. 3E Ch. 18.1 - Prob. 4E Ch. 18.1 - Prob. 5E Ch. 18.1 - Prob. 6E Ch. 18.1 - Prob. 7E Ch. 18.1 - Prob. 8E

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