EBK STARTING OUT WITH C++ FROM CONTROL
9th Edition
ISBN: 8220106714379
Author: GADDIS
Publisher: PEARSON
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Chapter 18, Problem 4RQE
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Self-referential data structure:
It is a data structure, contains sequence of elements which includes at least one pointer variable in type of its own kind.
The purpose of the self-referential data structure is that each variable maintains a link to another variable of the same type to forming a non-contiguous data structure. It is otherwise called as linked list.
It can be implemented to form other data structures such as list, stacks, queues and trees...
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
Chapter 18 Solutions
EBK STARTING OUT WITH C++ FROM CONTROL
Ch. 18.1 - Prob. 18.1CPCh. 18.1 - Prob. 18.2CPCh. 18.1 - Prob. 18.3CPCh. 18.1 - Prob. 18.4CPCh. 18.2 - Prob. 18.5CPCh. 18.2 - Prob. 18.6CPCh. 18.2 - Prob. 18.7CPCh. 18.2 - Prob. 18.8CPCh. 18.2 - Prob. 18.9CPCh. 18.2 - Prob. 18.10CP
Ch. 18 - Prob. 1RQECh. 18 - Prob. 2RQECh. 18 - Prob. 3RQECh. 18 - Prob. 4RQECh. 18 - Prob. 5RQECh. 18 - Prob. 6RQECh. 18 - Prob. 7RQECh. 18 - Prob. 8RQECh. 18 - Prob. 9RQECh. 18 - Prob. 10RQECh. 18 - Prob. 11RQECh. 18 - Prob. 12RQECh. 18 - Prob. 13RQECh. 18 - Prob. 14RQECh. 18 - Prob. 15RQECh. 18 - Prob. 16RQECh. 18 - Prob. 17RQECh. 18 - Prob. 18RQECh. 18 - Prob. 19RQECh. 18 - Prob. 20RQECh. 18 - Prob. 21RQECh. 18 - Prob. 22RQECh. 18 - Prob. 23RQECh. 18 - Prob. 24RQECh. 18 - Prob. 25RQECh. 18 - T F The programmer must know in advance how many...Ch. 18 - T F It is not necessary for each node in a linked...Ch. 18 - Prob. 28RQECh. 18 - Prob. 29RQECh. 18 - Prob. 30RQECh. 18 - Prob. 31RQECh. 18 - Prob. 32RQECh. 18 - Prob. 33RQECh. 18 - Prob. 34RQECh. 18 - Prob. 35RQECh. 18 - Prob. 1PCCh. 18 - Prob. 2PCCh. 18 - Prob. 3PCCh. 18 - Prob. 4PCCh. 18 - Prob. 5PCCh. 18 - Prob. 6PCCh. 18 - Prob. 7PCCh. 18 - List Template Create a list class template based...Ch. 18 - Prob. 9PCCh. 18 - Prob. 10PCCh. 18 - Prob. 11PCCh. 18 - Prob. 12PCCh. 18 - Prob. 13PCCh. 18 - Prob. 14PCCh. 18 - Prob. 15PC
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