Chapter 18, Problem 45A

To determine

(a)

The drawing length.

Answer to Problem 45A

The drawing length is $8.031^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $\frac{1^{″}}{2}=1^{″}$. The schematic diagram of the system is shown below.

  

Figure-(1)

Write the expression for the drawing length.

  $L_d=\left(S\right)\left(L\right)$ ...... (I)

Here, the drawing length is $L_d$, the scale on the drawing is $S$ and the size of part is $L$.

Calculation:

Substitute $B$ for $L_d$, $\frac{1}{2}$ for $S$ and $16.062^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}B=\left(\frac{1}{2}\right)\left(16.062^{″}\right)\\ =8.031^{″}\end{array}$

Conclusion:

The drawing length is $8.031^{″}$.

To determine

(b)

The drawing length.

Answer to Problem 45A

The drawing length is $1.124^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $4^{″}=1^{″}$.

Calculation:

Substitute $G$ for $L_d$, $4$ for $S$ and $0.281^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}G=\left(4\right)\left(0.281^{″}\right)\\ =1.124^{″}\end{array}$

Conclusion:

The drawing length is $1.124^{″}$.

To determine

(c)

The drawing length.

Answer to Problem 45A

The drawing length is $4.016^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $\frac{1^{″}}{4}=1^{″}$.

Calculation:

Substitute $B$ for $L_d$, $\frac{1}{4}$ for $S$ and $16.062^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}B=\left(\frac{1}{4}\right)\left(16.062^{″}\right)\\ =4.016^{″}\end{array}$

Conclusion:

The drawing length is $4.016^{″}$.

To determine

(d)

The drawing length.

Answer to Problem 45A

The drawing length is $1.720^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $2^{″}=1^{″}$.

Calculation:

Substitute $C$ for $L_d$, $2$ for $S$ and $1.360^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}C=\left(2\right)\left(1.360^{″}\right)\\ =1.720^{″}\end{array}$

Conclusion:

The drawing length is $1.720^{″}$.

To determine

(e)

The drawing length.

Answer to Problem 45A

The drawing length is $2.808^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $1\frac{1^{″}}{2}=1^{″}$.

Calculation:

Substitute $A$ for $L_d$, $1\frac{1}{2}$ for $S$ and $1.872^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}A=\left(1\frac{1}{2}\right)\left(1.872^{″}\right)\\ =\left(\frac{3}{2}\right)\left(1.872^{″}\right)\\ =2.808^{″}\end{array}$

Conclusion:

The drawing length is $2.808^{″}$.

To determine

(f)

The drawing length.

Answer to Problem 45A

The drawing length is $7.950^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $\frac{3^{″}}{4}=1^{″}$.

Calculation:

Substitute $E$ for $L_d$, $\frac{3}{4}$ for $S$ and $10.600^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}E=\left(\frac{3}{4}\right)\left(10.600^{″}\right)\\ =7.950^{″}\end{array}$

Conclusion:

The drawing length is $7.950^{″}$.

To determine

(g)

The drawing length.

Answer to Problem 45A

The drawing length is $1.125^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $3^{″}=1^{″}$.

Calculation:

Substitute $H$ for $L_d$, $3$ for $S$ and $0.375^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}H=\left(3\right)\left(0.375^{″}\right)\\ =1.125^{″}\end{array}$

Conclusion:

The drawing length is $1.125^{″}$.

To determine

(h)

The drawing length.

Answer to Problem 45A

The drawing length is $1.575^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $\frac{1^{″}}{8}=1^{″}$.

Calculation:

Substitute $F$ for $L_d$, $\frac{1}{8}$ for $S$ and $12.600^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}F=\left(\frac{1}{8}\right)\left(12.600^{″}\right)\\ =1.575^{″}\end{array}$

Conclusion:

The drawing length is $1.575^{″}$.

To determine

(i)

The drawing length.

Answer to Problem 45A

The drawing length is $5.300^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $\frac{1^{″}}{2}=1^{″}$.

Calculation:

Substitute $E$ for $L_d$, $\frac{1}{2}$ for $S$ and $10.600^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}E=\left(\frac{1}{2}\right)\left(10.600^{″}\right)\\ =5.300^{″}\end{array}$

Conclusion:

The drawing length is $5.300^{″}$.

To determine

(j)

The drawing length.

Answer to Problem 45A

The drawing length is $1.686^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $6^{″}=1^{″}$.

Calculation:

Substitute $G$ for $L_d$, $6$ for $S$ and $0.281^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}G=\left(6\right)\left(0.281^{″}\right)\\ =1.686^{″}\end{array}$

Conclusion:

The drawing length is $1.686^{″}$.

To determine

(k)

The drawing length.

Answer to Problem 45A

The drawing length is $9.450^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $\frac{3^{″}}{4}=1^{″}$.

Calculation:

Substitute $F$ for $L_d$, $\frac{3}{4}$ for $S$ and $12.600^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}F=\left(\frac{3}{4}\right)\left(12.600^{″}\right)\\ =9.450^{″}\end{array}$

Conclusion:

The drawing length is $9.450^{″}$.

To determine

(l)

The drawing length.

Answer to Problem 45A

The drawing length is $2.040^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $1\frac{1^{″}}{2}=1^{″}$.

Calculation:

Substitute $C$ for $L_d$, $1\frac{1^{″}}{2}$ for $S$ and $1.360^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}C=\left(1\frac{1^{″}}{2}\right)\left(1.360^{″}\right)\\ =\left(\frac{3^{″}}{2}\right)\left(1.360^{″}\right)\\ =2.040^{″}\end{array}$

Conclusion:

The drawing length is $2.040^{″}$.

To determine

(m)

The drawing length.

Answer to Problem 45A

The drawing length is $6.300^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $\frac{1^{″}}{2}=1^{″}$.

Calculation:

Substitute $F$ for $L_d$, $\frac{1^{″}}{2}$ for $S$ and $12.600^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}F=\left(\frac{1}{2}\right)\left(12.600^{″}\right)\\ =6.300^{″}\end{array}$

Conclusion:

The drawing length is $6.300^{″}$.

To determine

(n)

The drawing length.

Answer to Problem 45A

The drawing length is $0.843^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $3^{″}=1^{″}$.

Calculation:

Substitute $G$ for $L_d$, $3$ for $S$ and $0.281^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}G=\left(3\right)\left(0.281^{″}\right)\\ =0.843^{″}\end{array}$

Conclusion:

The drawing length is $0.843^{″}$.

To determine

(o)

The drawing length.

Answer to Problem 45A

The drawing length is $4.016^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $\frac{1^{″}}{4}=1^{″}$.

Calculation:

Substitute $B$ for $L_d$, $\frac{1}{4}$ for $S$ and 16.062" for $L$ in Equation (I).

Conclusion:

The drawing length is $4.016^{″}$.

To determine

(o)

The drawing length.

Answer to Problem 45A

The drawing length is $3.744^{″}$.

Explanation of Solution

Given information:

The scale on the drawing is $2^{″}=1^{″}$.

Calculation:

Substitute $A$ for $L_d$, $2$ for $S$ and $1.872^{″}$ for $L$ in Equation (I).

  $\begin{array}{c}A=\left(2\right)\left(1.872^{″}\right)\\ =3.744^{″}\end{array}$

Conclusion:

The drawing length is $3.744^{″}$.