Explanation Given: The given system is Calculation: Let us consider the mesh currents are I 1 , I 2 and I 3 Values of impedances are Z 1 = 2.2 kΩ Z 2 = j 5 kΩ Z 3 = 10 kΩ The modified network will look like We can see in the figure that there is a current source in between the two mesh. Therefore, we will have to use a super-mesh as shown below. Applying Kirchhoff's Voltage law in loop 1, − 5 V ∠ 0 ° + ( I 1 ) ( Z 1 ) + ( I 1 − I 2 ) ( Z 2 ) = 0 ( I 1 ) ( 2200 + j 5000 ) − I 2 ( j 5000 ) = 5 V ∠ 0 ° I 1 ( 2.2 + j 5 ) − I 2 ( j 5 ) = 5 mV ∠ 0 ° I 1 ( 0.44 + j ) − j I 2 = 1 mV ∠ 0 ° ..................... ( 1 ) Applying Kirchhoff's Voltage law in loop 2, ( I 2 − I 1 ) ( Z 2 ) − 20 V ∠ 0 ° + ( I 3 ) ( Z 3 ) = 0 ( I 1 ) ( − j 5000 ) + ( I 2

Laboratory Manual for Introductory Circuit Analysis

13th Edition

ISBN: 9780133923780

Author: Robert L. Boylestad, Gabriel Kousourou

Publisher: PEARSON

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Current Division Method

The generalized current divider formula is given by the following relation below,

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Chapter 18, Problem 43P

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Chapter 18, Problem 42P

Chapter 18, Problem 44P

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Chapter 18 Solutions

Laboratory Manual for Introductory Circuit Analysis

Ch. 18 - Discuss, in your own words, the difference between...Ch. 18 - Convert the voltage source in Fig. 18.62 to a...Ch. 18 - Convert the current source in Fig. 18.63 to a...Ch. 18 - Convert the votage source in Fig. 18.64(a) to a...Ch. 18 - Write the mesh equations for the network of Fig....Ch. 18 - Write the mesh equations for the network of Fig....Ch. 18 - Write the mesh equations for the network of Fig....Ch. 18 - Write the mesh equations for the network of Fig....Ch. 18 - Write the mesh equations for the network of Fig....Ch. 18 - Write the mesh equtions for the network of Fig....

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