Engineering Fundamentals
6th Edition
ISBN: 9780357112144
Author: Saeed Moaveni
Publisher: MISC PUBS
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Chapter 18, Problem 3P
To determine
Plot the
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Please solve all points
1: find out the optimal solution:
1- Reliability Function
2- Serial Configuration
3- M.T.T.F
4- Probability distribution function (P.D.F)
5- Failure rate function
:calculate the reliability of the system for the following Figure
0.90
0.80
0.95
0.80
0.80
0.94)
0.80
: A system containing four connected compounds in series, each one has a
distribution and its parameters as shown in the table below
Component Scale parameter
Shape parameter
1
100
1.20
2
150
0.87
3
510
-
1.80
4
720
1.00
Time: 1. Hrs
During the last ten days: In one of the productive operations, the electronic control calculator equipped
with No. of defects for a specific volume of samples as shown:
10 9
8
7
6
5
4
3
2
1
Day No.
6673 6976
7505
6991
7028 6960
7916
7010 6591
7350
Total No.
53
55
60
58
16
22
49
48
64
17
Defect No.
DRAW THAT & CHOOSE THE BEST
A-P chart.
B-C chart
1. Key functions of quality control include:
A) Control of design, materials received and products and conduct studies of operations
B-Design and develop reasonable specifications
C) The use of equipment that gives the required accuracy
D) Provide appropriate screening equipment
2. The basic principles of critical pathways are:
A-fragmentation of the system to the objectives of the secondary clear and specific
B-Drawing the network diagram
C-Finding the critical path
D- All of the above
3- The production system is the following:
A-An integral part of the plant's completion
B-An effective system to integrate the efforts of various…
Chapter 18 Solutions
Engineering Fundamentals
Ch. 18.2 - Prob. 1BYGCh. 18.2 - Prob. 2BYGCh. 18.2 - Prob. 3BYGCh. 18.2 - Prob. 4BYGCh. 18.2 - Prob. BYGVCh. 18.3 - Prob. 1BYGCh. 18.3 - Prob. 2BYGCh. 18.3 - Prob. 3BYGCh. 18.3 - Prob. BYGVCh. 18.4 - Prob. 1BYG
Ch. 18.4 - Prob. 2BYGCh. 18.4 - Prob. 3BYGCh. 18.4 - Prob. 4BYGCh. 18.4 - Prob. BYGVCh. 18.5 - Prob. 1BYGCh. 18.5 - Prob. 2BYGCh. 18.5 - Prob. 3BYGCh. 18.5 - Prob. 4BYGCh. 18.5 - Prob. BYGVCh. 18.6 - Prob. 1BYGCh. 18.6 - Prob. 2BYGCh. 18.6 - Prob. 3BYGCh. 18.6 - Prob. 4BYGCh. 18.6 - Prob. BYGVCh. 18.7 - Prob. 1BYGCh. 18.7 - Prob. 2BYGCh. 18.7 - Prob. BYGVCh. 18 - Prob. 1PCh. 18 - Prob. 2PCh. 18 - Prob. 3PCh. 18 - In Chapter 12, we explained that the electric...Ch. 18 - The deflection of a cantilevered beam supporting...Ch. 18 - Prob. 6PCh. 18 - Prob. 7PCh. 18 - Prob. 8PCh. 18 - Prob. 9PCh. 18 - Prob. 10PCh. 18 - Prob. 11PCh. 18 - Prob. 12PCh. 18 - Prob. 13PCh. 18 - Prob. 14PCh. 18 - A jet plane taking off creates a noise with a...Ch. 18 - Prob. 16PCh. 18 - Prob. 17PCh. 18 - Prob. 18PCh. 18 - Prob. 19PCh. 18 - Prob. 20PCh. 18 - Prob. 21PCh. 18 - Prob. 22PCh. 18 - Prob. 23PCh. 18 - Prob. 24PCh. 18 - Prob. 25PCh. 18 - Prob. 26PCh. 18 - Prob. 27PCh. 18 - Prob. 28PCh. 18 - Prob. 29PCh. 18 - Prob. 30PCh. 18 - Prob. 31PCh. 18 - Prob. 32PCh. 18 - Prob. 33PCh. 18 - Prob. 34PCh. 18 - Prob. 35PCh. 18 - Prob. 36PCh. 18 - Prob. 37PCh. 18 - Prob. 38PCh. 18 - Prob. 39PCh. 18 - Prob. 40PCh. 18 - Prob. 41PCh. 18 - Prob. 42PCh. 18 - Prob. 43PCh. 18 - Prob. 44PCh. 18 - Prob. 45P
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- ) We started a new production process and its study gave the total deviations The standard value (for 25 samples of the product, sample size 4) is .105 .Calculate the capacity of this process The product specification limits are: 6.30 = LSL 6.50 = USL Standard deviation in a manufacturing system is 0.038 = We made improvements to the system and the deviation has become Standard 0.030 = σ What is required is to calculate the estimated coefficient before and after the operation Optimization. What is your conclusion? : A find out the optimal solution: 1-Average Outgoing Quality AOQ 2- operating Characteristics Curve 100% Inspection 3-Acceptable Quality level 4- Average outgoing Quality AOQ 5- Capability Index CPKarrow_forwardFollowing are the data of gauge and discharge collected at a particular section of the river by stream gauging operation. Gauge reading Discharge Gauge reading Discharge (m) (cms) (m) (cms) 7.65 15 8.48 170 7.70 30 8.98 400 7.77 57 9.30 600 7.80 39 9.50 800 7.90 60 89 10.50 1500 7.91 100 11.10 2000 8.08 150 11.70 2400 1. Develop a rating curve for this stream at this section for use in estimating the discharge for a known gauge reading and fit a linear regression equation for use in estimation of stage for a known value of discharge. Use a value of 7.50 as the gauge reading corresponding to zero discharge. (20 pts) Equation 1 arith 2. What is the coefficient of correlation of the derived relationship? (10 pts) R2² arith Equation 2 log R2 log 3. Determine the stage for a discharge of 3500 cms (5 pts) 4. Determine the discharge for a stage of 15 m (5 pts) NB Do both arithmetic and logarithmic plotsarrow_forwardQ2/ A (2m x 4 m) rectangular flexible foundation is placed above the ground surface (G.S) for two layers of clay, each layer 10 m thick. The modulus of Elasticity (E.) of the upper layer is 13 MN/m² and that of the lower layer is 15 MN/m². The Poisson ratio is (u, = 0.6) for the two layers. The pressure (stress) of 100 kN/m²is distributed along the surface of foundation. Determine the rigid immediate settlement at the corner of the foundation using Elastic theory method?arrow_forward
- Q1/ Find the maximum allowable load for a square foundation (3 m x 3 m) placed vertically in cohesive soil? (Use Terzaghi equation) Note: Yt=Yeat=18 kN/m³ Depth of foundation = 1.5 m Depth of water table below the ground surface = 0.8 m Factor of safety 3 C=20 Yw = 10 kN/m³ = No vertical or inclined loadsarrow_forwardP.3.3 Oil of sp.gr. 0.9 flows through a vertical pipe (upwards). Two points A and B one above the other 40 cm apart in a pipe are connected by a U-tube carrying mercury. If the difference of pressure between A and B is 0.2 kg/cm², 1- Find the reading of the manometer. 2- If the oil flows through a horizontal pipe, find the reading in manometer for the same difference in pressure between A and B. Ans. 1- R= 0.12913 m, 2- R = 0.1575 m,arrow_forwardPlease solve the question by hand with a detailed explanation of the steps.arrow_forward
- Please solve the question by hand with a detailed explanation of the steps.arrow_forwardP.3.4 A mercury U-tube manometer is used to measure the pressure drop across an orifice in pipe. If the liquid that flowing through the orifice is brine of sp.gr. 1.26 and upstream pressure is 2 psig and the downstream pressure is (10 in Hg) vacuum, find the reading of manometer. Ans. R=394 mm Hgarrow_forwardProject management questionarrow_forward
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