Computer Science Illuminated
7th Edition
ISBN: 9781284155617
Author: Nell Dale, John Lewis
Publisher: Jones & Bartlett Learning
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Chapter 18, Problem 38E
a.
Program Plan Intro
Parity bit:
Parity bit is a simplest form of error detection code.
- A bit added to the end of a string of binary code is called as parity bit. It is otherwise called check bit.
- This parity bit indicates whether the number of bits in the binary code with the value 1 is even or odd.
- If the binary code contains even number of 1, it is referred to as even parity.
- If the binary code contains odd number of 1, it is referred to as odd parity.
- There are two types of parity bits:
- Even parity bit
- Odd parity bit
Even parity bit:
- Even parity bit is set to 1, if the count of one’s in a given binary code is odd without including the parity bit.
- Otherwise, it is set to 0, if the count of one’s in a given binary code is even.
b.
Explanation of Solution
Find the even parity bit of 8-bit code:
The parity bit for 8-bit binary code 10101010 (Consider the binary code is even parity) is determined by,
- The binary code 10101010 contains 4 one’s and 4 zeroes...
c.
Explanation of Solution
Find the even parity bit of 8-bit code:
The parity bit for 8-bit binary code 11111111 (Consider the binary code is even parity) is determined by,
- The binary code 11111111 contains 8 one’s and no zeroes...
d.
Explanation of Solution
Find the even parity bit of 8-bit code:
The parity bit for 8-bit binary code 00000000 (Consider the binary code is even parity) is determined by,
- The binary code 00000000 contains 8 zeroes and no ones...
e.
Explanation of Solution
Find the even parity bit of 8-bit code:
The parity bit for 8-bit binary code 11101111 (Consider the binary code is even parity) is determined by,
- The binary code 11101111 contains 7 one’s and 1 zero is present...
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Big State University
The Big State University course catalog reads as follows: "To enroll in MIS 260, which is an advanced
course, a student must complete two prerequisites: MIS 120 and MIS 222. A student who completes
either one of these prerequisites and obtains the instructor's permission, however, will be allowed to
take MIS 260."
Tasks
1. Create a decision table that describes the Big State University course catalog regarding eligibility for
MIS 260. Show all possible rules.
2. Simplify the table you just created. Describe the results.
3. Draw a simplified decision tree to represent the Big State University catalog. Describe the results.
4. Why might you use a decision tree rather than a decision table?
What is the ALU result if the 4-bit ALU Control signal is 0100? What happens if the ALU Control signal is 0101?
Chapter 18 Solutions
Computer Science Illuminated
Ch. 18 - Prob. 1ECh. 18 - Prob. 2ECh. 18 - Prob. 3ECh. 18 - Prob. 4ECh. 18 - Prob. 5ECh. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - Prob. 8ECh. 18 - Prob. 9ECh. 18 - Prob. 10E
Ch. 18 - Prob. 11ECh. 18 - Prob. 12ECh. 18 - Prob. 13ECh. 18 - Prob. 14ECh. 18 - Prob. 15ECh. 18 - Prob. 16ECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Prob. 19ECh. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Prob. 23ECh. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Prob. 33ECh. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36ECh. 18 - Prob. 37ECh. 18 - Prob. 38ECh. 18 - Prob. 39ECh. 18 - Prob. 40ECh. 18 - Prob. 41ECh. 18 - Prob. 42ECh. 18 - Prob. 43ECh. 18 - Prob. 44ECh. 18 - Prob. 45ECh. 18 - Prob. 46ECh. 18 - Prob. 47ECh. 18 - Prob. 48ECh. 18 - Prob. 49ECh. 18 - Prob. 50ECh. 18 - Prob. 51ECh. 18 - Prob. 52ECh. 18 - Prob. 53ECh. 18 - Prob. 54ECh. 18 - Prob. 55ECh. 18 - Prob. 56ECh. 18 - Prob. 57ECh. 18 - Prob. 58ECh. 18 - Prob. 59ECh. 18 - Prob. 60ECh. 18 - Prob. 61ECh. 18 - Prob. 1TQCh. 18 - Prob. 2TQCh. 18 - Prob. 3TQ
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