Computer Science Illuminated
7th Edition
ISBN: 9781284155617
Author: Nell Dale, John Lewis
Publisher: Jones & Bartlett Learning
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Question
Chapter 18, Problem 37E
a.
Program Plan Intro
Parity bit:
Parity bit is the simplest form of error detection code.
- A bit added at the end of a string of binary code is called as parity bit. It is otherwise called check bit.
- This parity bit indicates whether the number of bits in the binary code with the value 1 is even or odd.
- If the binary code contains even number of 1, it is referred to as even parity.
- If the binary code contains odd number of 1, it is referred to as odd parity.
- There are two types of parity bits:
- Even parity bit
- Odd parity bit
Odd parity bit:
- Odd parity bit is set to 1, if the count of one’s in a given binary code is even without including the parity bit.
- Otherwise, it is set to 0, if the count of one’s in a given binary code is odd.
b.
Explanation of Solution
Find the odd parity bit of 8-bit code:
The parity bit for 8-bit binary code 10101010 (Consider the binary code is odd parity) is determined by,
- The binary code 10101010 contains 4 one’s and 4 zeroes...
c.
Explanation of Solution
Find the odd parity bit of 8-bit code:
The parity bit for 8-bit binary code 11111111 (Consider the binary code is odd parity) is determined by,
- The binary code 11111111 contains 8 one’s and no zeroes...
d.
Explanation of Solution
Find the odd parity bit of 8-bit code:
The parity bit for 8-bit binary code 00000000 (Consider the binary code is odd parity) is determined by,
- The binary code 00000000 contains 8 zeroes and no ones...
e.
Explanation of Solution
Find the odd parity bit of 8-bit code:
The parity bit for 8-bit binary code 11101111 (Consider the binary code is odd parity) is determined by,
- The binary code 11101111 contains 7 one’s and 1 zero is present...
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21 22 23 24 25
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: The Multithreaded Cook
In this lab, we'll practice multithreading. Using Semaphores for synchronization, implement a
multithreaded cook that performs the following recipe, with each task being contained in a single Thread:
1. Task 1: Cut onions.
a.
Waits for none.
b. Signals Task 4
2. Task 2: Mince meat.
a. Waits for none
b. Signals Task 4
3. Task 3: Slice aubergines.
a. Waits for none
b. Signals Task 6
4. Task 4: Make sauce.
a. Waits for Task 1, and 2
b. Signals Task 6
5. Task 5: Finished Bechamel.
a. Waits for none
b. Signals Task 7
6. Task 6: Layout the layers.
a.
Waits for Task 3, and 4
b. Signals Task 7
7. Task 7: Put Bechamel and Cheese.
a.
Waits for Task 5, and 6
b. Signals Task 9
8. Task 8: Turn on oven.
a.
Waits for none
b. Signals Task 9
9. Task 9: Cook.
a. Waits for Task 7, and 8
b.
Signals none
At the start of each task (once all Semaphores have been acquired), print out a string of the task you are
starting, sleep for 2-11 seconds, then print out a string saying that you…
Programming Problems
9.28
Assume that a system has a 32-bit virtual address with a 4-KB page size.
Write a C program that is passed a virtual address (in decimal) on the
command line and have it output the page number and offset for the
given address. As an example, your program would run as follows:
./addresses 19986
Your program would output:
The address 19986 contains:
page number = 4
offset = 3602
Writing this program will require using the appropriate data type to
store 32 bits. We encourage you to use unsigned data types as well.
Programming Projects
Contiguous Memory Allocation
In Section 9.2, we presented different algorithms for contiguous memory allo-
cation. This project will involve managing a contiguous region of memory of
size MAX where addresses may range from 0 ... MAX - 1. Your program must
respond to four different requests:
1. Request for a contiguous block of memory
2. Release of a contiguous block of memory
3. Compact unused holes of memory into one single block
4.…
Chapter 18 Solutions
Computer Science Illuminated
Ch. 18 - Prob. 1ECh. 18 - Prob. 2ECh. 18 - Prob. 3ECh. 18 - Prob. 4ECh. 18 - Prob. 5ECh. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - Prob. 8ECh. 18 - Prob. 9ECh. 18 - Prob. 10E
Ch. 18 - Prob. 11ECh. 18 - Prob. 12ECh. 18 - Prob. 13ECh. 18 - Prob. 14ECh. 18 - Prob. 15ECh. 18 - Prob. 16ECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Prob. 19ECh. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Prob. 23ECh. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Prob. 33ECh. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36ECh. 18 - Prob. 37ECh. 18 - Prob. 38ECh. 18 - Prob. 39ECh. 18 - Prob. 40ECh. 18 - Prob. 41ECh. 18 - Prob. 42ECh. 18 - Prob. 43ECh. 18 - Prob. 44ECh. 18 - Prob. 45ECh. 18 - Prob. 46ECh. 18 - Prob. 47ECh. 18 - Prob. 48ECh. 18 - Prob. 49ECh. 18 - Prob. 50ECh. 18 - Prob. 51ECh. 18 - Prob. 52ECh. 18 - Prob. 53ECh. 18 - Prob. 54ECh. 18 - Prob. 55ECh. 18 - Prob. 56ECh. 18 - Prob. 57ECh. 18 - Prob. 58ECh. 18 - Prob. 59ECh. 18 - Prob. 60ECh. 18 - Prob. 61ECh. 18 - Prob. 1TQCh. 18 - Prob. 2TQCh. 18 - Prob. 3TQ
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