Determine a seasonal index for each of the four quarters.
Find the number of visitors for each quarter of 2017 if 10% increase in the total number of visitors in 2016.
Determine the trend equation.
Project the number of visitors for 2017.
Find the seasonally adjusted forecasts.
Identify the best forecast.
Answer to Problem 31CE
The seasonal indexes for the four quarters are 1.2046, 1.0206, 0.6297 and 01.1451, respectively.
The number of visitors for each quarter of 2017 if 10% increase in the total number of visitors in 2016 is 255.25 visitors per quarter.
The trend equation is
The number of visitors for 2017 are 242.0171, 248.634, 255.2509 and 261.8678.
The seasonally adjusted forecasts are 291.5338, 253.7559, 160.7315 and 299.8648.
The best forecast is the fourth quarter of 2017.
Explanation of Solution
Calculation:
Four-Year moving average:
Centered Moving Average:
Specific seasonal index:
Year | Quarter | Visitors |
Four-quarter moving average |
Centered Moving average | Specific seasonal |
2010 | 1 | 86 | |||
2 | 62 | ||||
3 | 28 | 70 | 0.4 | ||
4 | 94 | 67.5 | 75 | 1.253333 | |
2011 | 1 | 106 | 72.5 | 80 | 1.325 |
2 | 82 | 77.5 | 85 | 0.964706 | |
3 | 48 | 82.5 | 91.75 | 0.523161 | |
4 | 114 | 87.5 | 100.75 | 1.131514 | |
2012 | 1 | 140 | 96 | 109.75 | 1.275626 |
2 | 120 | 105.5 | 119 | 1.008403 | |
3 | 82 | 114 | 126.75 | 0.646943 | |
4 | 154 | 124 | 132 | 1.166667 | |
2013 | 1 | 162 | 129.5 | 136.75 | 1.184644 |
2 | 140 | 134.5 | 141.5 | 0.989399 | |
3 | 100 | 139 | 147.25 | 0.679117 | |
4 | 174 | 144 | 154.5 | 1.126214 | |
2014 | 1 | 188 | 150.5 | 162 | 1.160494 |
2 | 172 | 158.5 | 168.5 | 1.020772 | |
3 | 128 | 165.5 | 174 | 0.735632 | |
4 | 198 | 171.5 | 180.25 | 1.098474 | |
2015 | 1 | 208 | 176.5 | 187.25 | 1.110814 |
2 | 202 | 184 | 193.25 | 1.045278 | |
3 | 154 | 190.5 | 200.75 | 0.767123 | |
4 | 220 | 196 | 210.25 | 1.046373 | |
2016 | 1 | 246 | 205.5 | 219.5 | 1.120729 |
2 | 240 | 215 | 228 | 1.052632 | |
3 | 190 | 224 | |||
4 | 252 | 232 |
The Quarterly indexes are,
I | II | III | IV | |
2010 | 0.4 | 1.253333 | ||
2011 | 1.325 | 0.964706 | 0.523161 | 1.131514 |
2012 | 1.275626 | 1.008403 | 0.646943 | 1.166667 |
2013 | 1.184644 | 0.989399 | 0.679117 | 1.126214 |
2014 | 1.160494 | 1.020772 | 0.735632 | 1.098474 |
2015 | 1.110814 | 1.045278 | 0.767123 | 1.046373 |
2016 | 1.120729 | 1.052632 | ||
Mean | 1.1962 | 1.0135 | 0.6253 | 1.1371 |
Seasonal index:
Here,
Therefore,
The seasonal indexes are,
I | II | III | IV | |
2010 | 0.4 | 1.253333 | ||
2011 | 1.325 | 0.964706 | 0.523161 | 1.131514 |
2012 | 1.275626 | 1.008403 | 0.646943 | 1.166667 |
2013 | 1.184644 | 0.989399 | 0.679117 | 1.126214 |
2014 | 1.160494 | 1.020772 | 0.735632 | 1.098474 |
2015 | 1.110814 | 1.045278 | 0.767123 | 1.046373 |
2016 | 1.120729 | 1.052632 | ||
Mean | 1.1962 | 1.0135 | 0.6253 | 1.1371 |
Seasonal Index |
The total number of visitors in year 2016 is
The 10% of 928 visitors is
The number of visitors in 2017 is
Therefore, the number of visitors in each quarter of 2017 is
Trend Equation:
Step-by-step procedure to obtain the regression using the Excel:
- Enter the data for Year, Visitors and t in Excel sheet.
- Go to Data Menu.
- Click on Data Analysis.
- Select ‘Regression’ and click on ‘OK’
- Select the column of Visitors under ‘Input Y Range’.
- Select the column of t under ‘Input X Range’.
- Click on ‘OK’.
Output for the Regression obtained using the Excel is as follows:
From the output, the regression equation is
Projection of the number of visitors for 2017:
The t value for first quarter of 2017 is 29.
The t value for second quarter of 2017 is 30.
The t value for third quarter of 2017 is 31.
The t value for third quarter of 2017 is 32.
Seasonally Adjusted Forecast:
Estimated Visitors | Seasonal Index | |
242.0171 | 1.2046 | 291.5338 |
248.634 | 1.0206 | 253.7559 |
255.2509 | 0.6297 | 160.7315 |
261.8678 | 1.1451 | 299.8648 |
The seasonal index for the fourth quarter is high compared with remaining three quarters. Hence, the forecast for the fourth quarter is best.
Want to see more full solutions like this?
Chapter 18 Solutions
Gen Combo Ll Statistical Techniques In Business And Economics; Connect Ac
- Please answer the questionsarrow_forward30. An individual who has automobile insurance from a certain company is randomly selected. Let Y be the num- ber of moving violations for which the individual was cited during the last 3 years. The pmf of Y isy | 1 2 4 8 16p(y) | .05 .10 .35 .40 .10 a.Compute E(Y).b. Suppose an individual with Y violations incurs a surcharge of $100Y^2. Calculate the expected amount of the surcharge.arrow_forward24. An insurance company offers its policyholders a num- ber of different premium payment options. For a ran- domly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows: F(x)=0.00 : x < 10.30 : 1≤x<30.40 : 3≤ x < 40.45 : 4≤ x <60.60 : 6≤ x < 121.00 : 12≤ x a. What is the pmf of X?b. Using just the cdf, compute P(3≤ X ≤6) and P(4≤ X).arrow_forward
- 59. At a certain gas station, 40% of the customers use regular gas (A1), 35% use plus gas (A2), and 25% use premium (A3). Of those customers using regular gas, only 30% fill their tanks (event B). Of those customers using plus, 60% fill their tanks, whereas of those using premium, 50% fill their tanks.a. What is the probability that the next customer will request plus gas and fill the tank (A2 B)?b. What is the probability that the next customer fills the tank?c. If the next customer fills the tank, what is the probability that regular gas is requested? Plus? Premium?arrow_forward38. Possible values of X, the number of components in a system submitted for repair that must be replaced, are 1, 2, 3, and 4 with corresponding probabilities .15, .35, .35, and .15, respectively. a. Calculate E(X) and then E(5 - X).b. Would the repair facility be better off charging a flat fee of $75 or else the amount $[150/(5 - X)]? [Note: It is not generally true that E(c/Y) = c/E(Y).]arrow_forward74. The proportions of blood phenotypes in the U.S. popula- tion are as follows:A B AB O .40 .11 .04 .45 Assuming that the phenotypes of two randomly selected individuals are independent of one another, what is the probability that both phenotypes are O? What is the probability that the phenotypes of two randomly selected individuals match?arrow_forward
- 53. A certain shop repairs both audio and video compo- nents. Let A denote the event that the next component brought in for repair is an audio component, and let B be the event that the next component is a compact disc player (so the event B is contained in A). Suppose that P(A) = .6 and P(B) = .05. What is P(BA)?arrow_forward26. A certain system can experience three different types of defects. Let A;(i = 1,2,3) denote the event that the sys- tem has a defect of type i. Suppose thatP(A1) = .12 P(A) = .07 P(A) = .05P(A, U A2) = .13P(A, U A3) = .14P(A2 U A3) = .10P(A, A2 A3) = .011Rshelfa. What is the probability that the system does not havea type 1 defect?b. What is the probability that the system has both type 1 and type 2 defects?c. What is the probability that the system has both type 1 and type 2 defects but not a type 3 defect? d. What is the probability that the system has at most two of these defects?arrow_forwardThe following are suggested designs for group sequential studies. Using PROCSEQDESIGN, provide the following for the design O’Brien Fleming and Pocock.• The critical boundary values for each analysis of the data• The expected sample sizes at each interim analysisAssume the standardized Z score method for calculating boundaries.Investigators are evaluating the success rate of a novel drug for treating a certain type ofbacterial wound infection. Since no existing treatment exists, they have planned a one-armstudy. They wish to test whether the success rate of the drug is better than 50%, whichthey have defined as the null success rate. Preliminary testing has estimated the successrate of the drug at 55%. The investigators are eager to get the drug into production andwould like to plan for 9 interim analyses (10 analyzes in total) of the data. Assume thesignificance level is 5% and power is 90%.Besides, draw a combined boundary plot (OBF, POC, and HP)arrow_forward
- Please provide the solution for the attached image in detailed.arrow_forward20 km, because GISS Worksheet 10 Jesse runs a small business selling and delivering mealie meal to the spaza shops. He charges a fixed rate of R80, 00 for delivery and then R15, 50 for each packet of mealle meal he delivers. The table below helps him to calculate what to charge his customers. 10 20 30 40 50 Packets of mealie meal (m) Total costs in Rands 80 235 390 545 700 855 (c) 10.1. Define the following terms: 10.1.1. Independent Variables 10.1.2. Dependent Variables 10.2. 10.3. 10.4. 10.5. Determine the independent and dependent variables. Are the variables in this scenario discrete or continuous values? Explain What shape do you expect the graph to be? Why? Draw a graph on the graph provided to represent the information in the table above. TOTAL COST OF PACKETS OF MEALIE MEAL 900 800 700 600 COST (R) 500 400 300 200 100 0 10 20 30 40 60 NUMBER OF PACKETS OF MEALIE MEALarrow_forwardLet X be a random variable with support SX = {−3, 0.5, 3, −2.5, 3.5}. Part ofits probability mass function (PMF) is given bypX(−3) = 0.15, pX(−2.5) = 0.3, pX(3) = 0.2, pX(3.5) = 0.15.(a) Find pX(0.5).(b) Find the cumulative distribution function (CDF), FX(x), of X.1(c) Sketch the graph of FX(x).arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALTrigonometry (MindTap Course List)TrigonometryISBN:9781305652224Author:Charles P. McKeague, Mark D. TurnerPublisher:Cengage Learning
- Big Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin HarcourtCollege Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning