(a) Explanation Given info: The number of moles of gas is 67.5 mol . The relation according to the ideal gas equation is, P V = n R T (1) Rewrite the equation (1) to find the temperature at point A , T A = P A V A n R Here, n is the number of moles of the gas. P A is the pressure of the gas at point A . V A is the volume occupied by the gas at point A . R is the universal gas constant. Substitute 1.00 m 3 for V A , 150 kPa for P A , 67.9 mol for n and 8.31 J / mol ⋅ K for R in above equation to find the value of T A . T A = ( 150 kPa × 10 3 Pa 1 kPa ) ( 1.00 m 3 ) ( 67.9 mol ) ( 8.31 J / mol ⋅ K ) = 267 K Thus, the temperature at point A is 267 K . Rewrite the equation (1) to find the temperature at point B , T B = P B V B n R Here, P B is the pressure of the gas at point B . V B is the volume occupied by the gas at point B . Substitute 4.00 m 3 for V B , 50 kPa for P B , 67.9 mol for n and 8.31 J / mol ⋅ K for R in above equation to find the value of T B (b) To determine The heat enters or leaves the system for process A → B , B → C and C → A . (c) To determine The heat exchanged with the gas in process A → B , B → C and C → A .

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ISBN: 9780134051802

Author: Walker

Publisher: PEARSON

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First law of Thermodynamics

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Chapter 18, Problem 27PCE

(a)

To determine

The temperature at point A , B and C .

(b)

To determine

The heat enters or leaves the system for process A→B , B→C and C→A .

(c)

To determine

The heat exchanged with the gas in process A→B , B→C and C→A .

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Chapter 18, Problem 26PCE

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Chapter 18 Solutions

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The temperature at point A , B and C .

Solution Summary: The author explains the temperature at point A, B and C. The relation according to the ideal gas equation is PV=nRT

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The temperature at point A , B and C .

The heat enters or leaves the system for process A→B , B→C and C→A .

The heat exchanged with the gas in process A→B , B→C and C→A .

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Chapter 18 Solutions