STATISTICAL TECHNIQUES IN BUS.+ECON.
18th Edition
ISBN: 9781260239478
Author: Lind
Publisher: RENT MCG
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Chapter 18, Problem 25CE
To determine
To explain: The type of time series pattern if a time series analysis reports that the seasonal indexes are all equal to
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30. An individual who has automobile insurance from a certain company is randomly selected. Let Y be the num- ber of moving violations for which the individual was cited during the last 3 years. The pmf of Y isy | 1 2 4 8 16p(y) | .05 .10 .35 .40 .10
a.Compute E(Y).b. Suppose an individual with Y violations incurs a surcharge of $100Y^2. Calculate the expected amount of the surcharge.
24. An insurance company offers its policyholders a num- ber of different premium payment options. For a ran- domly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows:
F(x)=0.00 : x < 10.30 : 1≤x<30.40 : 3≤ x < 40.45 : 4≤ x <60.60 : 6≤ x < 121.00 : 12≤ x
a. What is the pmf of X?b. Using just the cdf, compute P(3≤ X ≤6) and P(4≤ X).
Chapter 18 Solutions
STATISTICAL TECHNIQUES IN BUS.+ECON.
Ch. 18 - Prob. 1ECh. 18 - Prob. 2ECh. 18 - Prob. 3ECh. 18 - Prob. 4ECh. 18 - Prob. 1SRCh. 18 - Prob. 5ECh. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - Prob. 8ECh. 18 - Prob. 2SR
Ch. 18 - Prob. 9ECh. 18 - Prob. 10ECh. 18 - Prob. 11ECh. 18 - Prob. 12ECh. 18 - Prob. 3SRCh. 18 - Prob. 13ECh. 18 - Prob. 14ECh. 18 - Prob. 15ECh. 18 - Prob. 16ECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Prob. 4SRCh. 18 - Prob. 19ECh. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Prob. 23CECh. 18 - Prob. 24CECh. 18 - Prob. 25CECh. 18 - Prob. 26CECh. 18 - Prob. 27CECh. 18 - Prob. 28CECh. 18 - Prob. 29CECh. 18 - Prob. 30CECh. 18 - Prob. 31CECh. 18 - Prob. 32CECh. 18 - Prob. 33CECh. 18 - Prob. 34CECh. 18 - Prob. 35CECh. 18 - Prob. 1PCh. 18 - Prob. 2PCh. 18 - Prob. 3PCh. 18 - Prob. 1.1PTCh. 18 - Prob. 1.2PTCh. 18 - Prob. 1.3PTCh. 18 - Prob. 1.4PTCh. 18 - Prob. 1.5PTCh. 18 - Prob. 1.6PTCh. 18 - Prob. 1.7PTCh. 18 - Prob. 1.8PTCh. 18 - Prob. 1.9PTCh. 18 - Prob. 1.10PTCh. 18 - Prob. 2.1PTCh. 18 - Prob. 2.2PTCh. 18 - Prob. 2.3PT
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