
Concept explainers
(a)
Interpretation:
The base and sugar in the deoxythymidine nucleoside needs to be identified.
Concept Introduction:
DNA and RNA are composed of few main components;
The combination of nitrogenous base and sugar molecule is called as nucleoside which further bonded with phosphate group. The bonding of nucleoside with phosphate group makes
(b)
Interpretation:
The base and sugar in the adenosine nucleoside needs to be identified.
Concept Introduction:
DNA and RNA are composed of few main components;
The combination of nitrogenous base and sugar molecule is called as nucleoside which further bonded with phosphate group. The bonding of nucleoside with phosphate group makes nucleotide which further polymerises to form DNA and RNA.
(c)
Interpretation:
The base and sugar in the cytidine nucleoside needs to be identified.
Concept Introduction:
DNA and RNA are composed of few main components;
The combination of nitrogenous base and sugar molecule is called as nucleoside which further bonded with phosphate group. The bonding of nucleoside with phosphate group makes nucleotide which further polymerise to form DNA and RNA.
(d)
Interpretation:
The base and sugar in the deoxyguanosine nucleoside needs to be identified.
Concept Introduction:
DNA and RNA are composed of few main components;
The combination of nitrogenous base and sugar molecule is called as nucleoside which further bonded with phosphate group. The bonding of nucleoside with phosphate group makes nucleotide which further polymerises to form DNA and RNA.

Want to see the full answer?
Check out a sample textbook solution
Chapter 18 Solutions
EBK BASIC CHEMISTRY
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





