Explanation Given information: The fundamental frequency of the sound is 300 Hz . Formula to calculate the fundamental frequency is, f = 1 2 L T μ f is the fundamental frequency. L is the length of the wire. T is the tension in the wire. μ is the linear mass density of water. The above equation shows that, f ∝ T Therefore, f 1 ′ f 1 = T 2 T 1 f 1 ′ = f 1 T 2 T 1 (I) T 1 is the tension in wire when it is hanging. T 2 is the tension in the wire when it is submerged in water. f 1 ′ is the new fundamental frequency when object is submerged in water. f 1 is the fundamental frequency when it is hanging. At equilibrium of the object, T 1 − m g = 0 T 1 = m g m is the mass of the object. g is the acceleration due to gravity. Formula to calculate the buoyant force is, B = ρ w V w g B is the buoyant force. ρ w is the density of water. V w is the volume of water displaced by object. Apply the equilibrium condition when it is submerged in water. B + T 2 − m g = 0 T 2 = m g − B Substitute ρ w V w g for B in the above equation. T 2 = m g − ρ w V w g For the lowest possible frequency, the tension T 2 must be lowest

Physics for Scientists and Engineers (AP Edition)

9th Edition

ISBN: 9781133953951

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 18, Problem 18.79AP

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Chapter 18 Solutions

Physics for Scientists and Engineers (AP Edition)

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The lowest possible new fundamental frequency.

Solution Summary: The author explains the formula to calculate the fundamental frequency and the buoyant force.

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