(a) Explanation Given information: The mass of the string is 4.80 g , the length of the string is 2.0 m , tension in the string is 48.0 N and the string is vibrates in its second n = 2 mode. Formula to calculate the linear mass density is, μ = m L μ is the linear mass density of the string. m is the mass of the string. L is the length of the string. Formula to calculate the speed of the wave in the string is, v st = T μ v st is the speed of the wave in the string. T is the tension in the wire. Substitute m L for μ in the above equation. v st = T m L = T L m Substitute 48.0 N for T , 4 (b) To determine The ratio of the wavelength in air of the sound emitted by vibrating string and the wavelength of the wave on the string.

Physics for Scientists and Engineers (AP Edition)

9th Edition

ISBN: 9781133953951

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 18, Problem 18.68AP

(a)

To determine

Whether the wavelength in air of the sound emitted by the vibrating string larger or smaller than the wavelength of the wave on the string.

(b)

To determine

The ratio of the wavelength in air of the sound emitted by vibrating string and the wavelength of the wave on the string.

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Chapter 18, Problem 18.67AP

Chapter 18, Problem 18.69AP

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Chapter 18 Solutions

Physics for Scientists and Engineers (AP Edition)

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Whether the wavelength in air of the sound emitted by the vibrating string larger or smaller than the wavelength of the wave on the string.

Solution Summary: The author explains that the wavelength of sound emitted by the vibrating string is larger or smaller than the wave on the string.

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Whether the wavelength in air of the sound emitted by the vibrating string larger or smaller than the wavelength of the wave on the string.

The ratio of the wavelength in air of the sound emitted by vibrating string and the wavelength of the wave on the string.

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Chapter 18 Solutions