The pH of the solution has to be calculated for 0 .175 M HY (K a = 1 .50 × 10 − 4 ) . Concept introduction: An equilibrium constant ( K ) is the ratio of concentration of products and reactants raised to appropriate stoichiometric coefficient at equlibrium. For the general acid HA, HA ( aq ) + H 2 O ( l ) ⇌ H 3 O + ( aq ) + A − ( aq ) The relative strength of an acid and base in water can be also expressed quantitatively with an equilibrium constant as follows: K a = [ H 3 O + ] [ A − ] [ HA ] ( 1 ) An equilibrium constant ( K ) with subscript a indicate that it is an equilibrium constant of an acid in water. Acid - dissociation constants can be expressed as pK a values, pK a = -log K a and 10 - pK a = K a Percent dissociation can be calculated by using following formula, Percent dissociated = dissociation initial ×100 The K a value is calculating by using following formula, K w = K a × K b
The pH of the solution has to be calculated for 0 .175 M HY (K a = 1 .50 × 10 − 4 ) . Concept introduction: An equilibrium constant ( K ) is the ratio of concentration of products and reactants raised to appropriate stoichiometric coefficient at equlibrium. For the general acid HA, HA ( aq ) + H 2 O ( l ) ⇌ H 3 O + ( aq ) + A − ( aq ) The relative strength of an acid and base in water can be also expressed quantitatively with an equilibrium constant as follows: K a = [ H 3 O + ] [ A − ] [ HA ] ( 1 ) An equilibrium constant ( K ) with subscript a indicate that it is an equilibrium constant of an acid in water. Acid - dissociation constants can be expressed as pK a values, pK a = -log K a and 10 - pK a = K a Percent dissociation can be calculated by using following formula, Percent dissociated = dissociation initial ×100 The K a value is calculating by using following formula, K w = K a × K b
Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.
Chapter 18, Problem 18.75P
(a)
Interpretation Introduction
Interpretation:
The pH of the solution has to be calculated for 0.175 M HY (Ka = 1.50×10−4).
Concept introduction:
An equilibrium constant(K) is the ratio of concentration of products and reactants raised to appropriate stoichiometric coefficient at equlibrium.
For the general acid HA,
HA(aq)+H2O(l)⇌H3O+(aq)+A−(aq)
The relative strength of an acid and base in water can be also expressed quantitatively with an equilibrium constant as follows:
Ka=[H3O+][A−][HA](1)
An equilibrium constant (K) with subscript a indicate that it is an equilibrium constant of an acid in water.
Acid - dissociation constants can be expressed as pKa values,pKa = -log Ka and10 - pKa = Ka
Percent dissociation can be calculated by using following formula,
Percent dissociated = dissociationinitial×100
The Ka value is calculating by using following formula,
Kw = Ka × Kb
(b)
Interpretation Introduction
Interpretation:
The pOH of the solution has to be calculated for 0.175 M HX (Ka = 2.00×10−2).
Concept introduction:
An equilibrium constant(K) is the ratio of concentration of products and reactants raised to appropriate stoichiometric coefficient at equlibrium.
For the general acid HA,
HA(aq)+H2O(l)⇌H3O+(aq)+A−(aq)
The relative strength of an acid and base in water can be also expressed quantitatively with an equilibrium constant as follows:
Ka=[H3O+][A−][HA](1)
An equilibrium constant (K) with subscript a indicate that it is an equilibrium constant of an acid in water.
Acid - dissociation constants can be expressed as pKa values,pKa = -log Ka and10 - pKa = Ka
Percent dissociation can be calculated by using following formula,
Percent dissociated = dissociationinitial×100
The Ka value is calculating by using following formula,
Part C
IN
H
N.
Br₂ (2 equiv.)
AlBr3
Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and
+
e
(×)
H± 12D
T
EXP.
L
CONT.
ד
9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer
appropriately in the box. Only the answer in the box will be graded. (3) points)
OH
OH
بر بد بدید
2
3
There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS).
Ca, ppm
V, ppm
SCa, arb. units
SV, arb. units
20.0
10.0
14375.11
14261.02
40.0
10.0
36182.15
17997.10
60.0
10.0
39275.74
12988.01
80.0
10.0
57530.75
14268.54
100.0…
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