Chapter 18, Problem 18.62P

Interpretation Introduction

Interpretation:

Solution that has $H_3{O}^{+}$ is approximately equal to $\left[C{H}_{3}CO{O}^{-}\right]$ has to be identified and explained from (a) $\text{0}{\text{.1 M CH}}_{\text{3}}\text{COOH}$, (b) ${\text{1×10}}^{\text{-7}}{\text{ M CH}}_{\text{3}}\text{COOH}$; (c) a solution containing both $\text{0}{\text{.1 M CH}}_{\text{3}}\text{COOH and 0}{\text{.1 M CH}}_{\text{3}}\text{COONa}$.

Concept introduction:

A solution may be acidic and basic depends on relative strength of anions as an acid or base. Anions and cations can be acidic, basic and netural. Acidic have $\text{pH < 7}$, basic have $\text{pH > 7}$ and netural have $\text{pH=7}$.

The $\text{pH}$ is decreases when the solution is more acidic (less basic) similarly the $\text{pH}$ is increase when the solution is more basic (less acidic).

The Relationships among $\text{pH, pOH, and pKw}$

  $\begin{array}{l}\text{pH = -}\text{log}{\text{(H}}_{\text{3}}{\text{O}}^{\text{+}}\text{)}\\ \left[{\text{H}}_{\text{3}}{\text{O}}^{\text{+}}\right]={10}^{-\text{pH}}\\ \text{pOH = -}\text{log}{\text{(OH}}^{-}\text{)}\\ \left[{\text{OH}}^{-}\right]={10}^{-\text{pOH }}\end{array}$

  ${\text{pK}}_{\text{w}}\text{ = pH + pOH = 14}\text{.00 }$