Concept explainers
Videos
Draw structures of the following derivatives.
- a. the 2,4-dinitrophenylhydrazone of benzaldehyde
- b. the semicarbazone of cyclobutanone
- c. cyclopropanone oxime
- d. the ethylene acetal of hexan-3-one
- e. acetaldehyde dimethyl acetal
- f. the methyl hemiacetal of formaldehyde
- g. the (E) isomer of the ethyl imine of propiophenone
- h. the hemiacetal form of 5-hydroxypentanal
(a)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 1.
Explanation of Solution
The given derivative is 2,4-dinitrophenylhydrazone of benzaldehyde.
The 2,4-dinitrophenylhydrazine is treated with benzaldehyde to form a 2,4-dinitrophenylhydrazone derivative.
The structure of 2,4-dinitrophenylhydrazone of benzaldehyde is given as,
Figure 1
(b)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 2.
Explanation of Solution
The given derivative is semicarbazone of cyclobutanone.
The cyclobutanone is treated with semicarbazide to form a semicarbazone derivative.
The structure of semicarbazone of cyclobutanone is given as,
Figure 2
(c)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 3.
Explanation of Solution
The given derivative is cyclopropanone oxime.
The cyclopropanone is treated with hydroxylamine to form an oxime.
The structure of cyclopropanone oxime is given as,
Figure 3
(d)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 4.
Explanation of Solution
The given derivative is ethylene acetal of hexan-3-one.
The ethylene glycol is treated with hexan-3-one to form ethylene acetal of hexan-3-one.
The structure of ethylene acetal of hexan-3-one is given as,
Figure 4
(e)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 5.
Explanation of Solution
The given derivative is acetaldehyde dimethyl acetal.
The acetaldehyde is treated with two moles of ethyl alcohol to form acetaldehyde dimethyl acetal.
The structure of acetaldehyde dimethyl acetal is given as,
Figure 5
(f)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 6.
Explanation of Solution
The given derivative is methyl hemiacetal of formaldehyde.
The structure of hemiacetal of formaldehyde is given as,
Figure 6
(g)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 7.
Explanation of Solution
The given derivative is (E)-isomer of the ethyl imine of propiophenone.
The propiophenone is treated with ethyl amine to form an ethyl imine derivative.
The structure of (E)-isomer of the ethyl imine of propiophenone is given as,
Figure 7
(h)
Interpretation:
The structure of the given derivative is to be drawn.
Concept introduction:
Ketones and aldehydes show different types of reactions which results to form many different products. The nucleophilic addition reactions are the common reactions, which form products like imines, diols, alcohols, cyanohydrins, and alkenes.
Answer to Problem 18.37SP
The structure of the given derivative is shown in Figure 8.
Explanation of Solution
The given derivative is hemiacetal of 5-hydroxypentanal.
The structure of hemiacetal of 5-hydroxypentanal is given as,
Figure 8
Want to see more full solutions like this?
Chapter 18 Solutions
Organic Chemistry (9th Edition)
- Use diagram to answer the following: 1.Is the overall rxn endo- or exothermic. Explain briefly your answer____________________2. How many steps in this mechanism?_____________3. Which is the rate determining step? Explain briefly your answer____________________4. Identify (circle and label) the reactants,the products and intermediate (Is a Cation, Anion, or a Radical?) Please explain and provide full understanding.arrow_forwardDraw the entire mechanism and add Curved Arrows to show clearly how electrons areredistributed in the process. Please explain and provide steps clearly.arrow_forward15) Create Lewis structure Br Brarrow_forward
- LIOT S How would you make 200. mL of a 0.5 M solution of CuSO4 5H2O from solid copper (II) sulfate? View Rubricarrow_forwardSteps and explantions pleasearrow_forwardMatch the denticity to the ligand. Water monodentate ✓ C₂O2 bidentate H₂NCH₂NHCH2NH2 bidentate x EDTA hexadentate Question 12 Partially correct Mark 2 out of 2 Flag question Provide the required information for the coordination compound shown below: Na NC-Ag-CN] Number of ligands: 20 Coordination number: 2✔ Geometry: linear Oxidation state of transition metal ion: +3 x in 12 correct out of 2 question Provide the required information for the coordination compound shown below. Na NC-Ag-CN] Number of ligands: 20 Coordination number: 2 Geometry: linear 0 Oxidation state of transition metal ion: +3Xarrow_forward
- Can you explain step by step behind what the synthetic strategy would be?arrow_forwardPlease explain step by step in detail the reasoning behind this problem/approach/and answer. thank you!arrow_forward2. Predict the product(s) that forms and explain why it forms. Assume that any necessary catalytic acid is present. .OH HO H₂N OHarrow_forward
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Macroscale and Microscale Organic ExperimentsChemistryISBN:9781305577190Author:Kenneth L. Williamson, Katherine M. MastersPublisher:Brooks Cole