Applied Fluid Mechanics
7th Edition
ISBN: 9780133414622
Author: UNTENER
Publisher: YUZU
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Textbook Question
Chapter 18, Problem 18.23PP
An air compressor delivers
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=
The forces F₁ = 590 lb, F₂ = 380 lb, F3 = 240 lb and F
330 lb. Determine the forces in each member of the truss.
Use positive values to indicate tension and negative values to
indicate compression.
a
a
a
D
b
F₁
A
000
B.
779977
F₂V
H
G
E
F4
b
BY NC SA
2013 Michael Swanbom
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
Variable Value
a
6 ft
b
10.1 ft
The force in member AB is
lb.
The force in member AH is
lb.
The force in member GH is
lb.
The force in member BH is
lb.
The force in member BC is
lb.
The force in member BG is
lb.
The force in member EG is
lb.
The force in member CD is
lb.
The force in member DE is
lb.
The force in member CE is
lb.
The force in member CG is
lb.
Multiple Choice
Circle the best answer to each statement.
1. Which type of surface deviation is controlled by a cy-
lindricity tolerance but not by a circularity tolerance?
A.
B.
C.
Ovality
Taper
Lobing
D. None of the above
2. When verifying a cylindricity tolerance, the inspec-
tion method must be able to collect a set of points and
determine the:
A. Distance between two coaxial cylinders that con-
tain the set of points
B.
Cylinder that circumscribes the set of points
C. Cylinder that inscribes the set of points
D.
Distance between two coaxial circles that contain
the set of points
3. Where Rule #1 applies to a cylindrical regular feature
of size, the tolerance value of a cylindricity tolerance
applied to the feature of size must be
tolerance.
A. Less than
B. Equal to
C. Greater than
D. None of the above
the size
4. Which of the following modifiers may be applied with
a cylindricity tolerance?
A. M
B.
C. ℗
D. Ø
5. Which geometric tolerance can provide an indirect
cylindricity…
The beam AB is attached to the wall in the xz plane by a
fixed support at A. A force of
F = (−129î + 69.0ĵ + 3591) N is applied to the end of
the beam at B. The weight of the beam can be modeled with
a uniform distributed load of intensity w = 85.0 N/m acting in
the negative z direction along its entire length. Find the
support reactions at A.
Z
с
A
b
a
B
F
y
Cc 10
BY NC SA
2016 Eric Davishahl
X
Values for dimensions on the figure are given in the following.
table. Note the figure may not be to scale.
Variable
Value
a
5.60 m
b
5.00 m
C
3.70 m
A
II
=
MA = (
m
2.>
~.>
+
+
k) N
k) N-
Chapter 18 Solutions
Applied Fluid Mechanics
Ch. 18 - A pipe in a compressed air system is carrying 2650...Ch. 18 - Prob. 18.2PPCh. 18 - Prob. 18.3PPCh. 18 - A duct in a heating system carries 8320 cfm....Ch. 18 - The velocity of flow in a ventilation duct is 1140...Ch. 18 - Prob. 18.6PPCh. 18 - Prob. 18.7PPCh. 18 - Prob. 18.8PPCh. 18 - Prob. 18.9PPCh. 18 - Prob. 18.10PP
Ch. 18 - Prob. 18.11PPCh. 18 - Describe a centrifugal fan with forward-curved...Ch. 18 - Prob. 18.13PPCh. 18 - Prob. 18.14PPCh. 18 - Name four types of positive-displacement...Ch. 18 - Name a type of compressor often used for pneumatic...Ch. 18 - Prob. 18.17PPCh. 18 - Prob. 18.18PPCh. 18 - Prob. 18.19PPCh. 18 - Compute the specific weight of nitrogen at 32...Ch. 18 - Compute the specific weight of air at 1260...Ch. 18 - Prob. 18.22PPCh. 18 - An air compressor delivers 820 cfm of free air....Ch. 18 - Prob. 18.24PPCh. 18 - Prob. 18.25PPCh. 18 - Prob. 18.26PPCh. 18 - Specify a size of Schedule 40 steel pipe suitable...Ch. 18 - For an aeration process, a sewage treatment plant...Ch. 18 - Prob. 18.29PPCh. 18 - Prob. 18.30PPCh. 18 - Prob. 18.31PPCh. 18 - Prob. 18.32PPCh. 18 - Prob. 18.33PPCh. 18 - Prob. 18.34PPCh. 18 - Prob. 18.35PPCh. 18 - Figure 18.14 iD shows a two-compartment vessel....Ch. 18 - Prob. 18.37PPCh. 18 - Prob. 18.38PPCh. 18 - Prob. 18.39PPCh. 18 - A tank of Refrigerant is at 150 kPa gage and 20C....Ch. 18 - Prob. 18.41PP
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- need help?arrow_forwardA bent pipe is attached to a wall with brackets as shown. A force of F = 180 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. Determine the support reactions at the brackets B, C, and D. Model these brackets as journal bearings (only force reactions perpendicular to the axis of the tube) and neglect couple moment reactions. Assume the distance between the supports at B and C and the tube bends nearby are negligible such that the support at C is directly above the support at D and the dimension g gives the distance between supports B and C. Enter your answers in Cartesian components. 2013 Michael Swanbom cc 10 BY NC SA g h א B 8° У A C x каж Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Variable Value a 6.72 in b 11.8 in с 14.8 in d 42.0 in h 26.6 in g 28.0 in → The reaction at B is B = lb. The reaction at C is C = lb. The reaction at D is D = lb. + << + + 2. + + 557 〈んarrow_forwardThe force F1 = 10 kN, F2 = 10 kN, F3 = 10 kN, F4 = 5 KN are acting on the sttructure shown. Determine the forces in the members specified below. Use positive values to indicate tension and negative values to indicate compression. F2 D b F1 F3 C E b F4 b B F a G Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 3 m b 4 m The force in member BC is KN. The force in member BE is KN. The force in member EF is KN.arrow_forward
- h = The transmission tower is subjected to the forces F₁ 3.6 KN at 50° and F2 = 3.3 kN at = 35°. Determine the forces in members BC, BP, PQ, PC, CD, DP and NP. Use positive values to indicate tension and negative values to indicate compression. 不 кажаж в *а*аж E N M d d IF, c B CENTER LINE S อ K F₂ Kbb cc 10 BY NC SA 2013 Michael Swanbom Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.7 m b 4.9 m с 3 m d 5.2 m h 8.4 m Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.7 m 4.9 m с 3 m d 5.2 m h 8.4 m The force in member BC is KN. The force in member BP is KN. The force in member PQ is KN. The force in member PC is KN. The force in member CD is KN. The force in member DP is KN. The force in member NP is KN.arrow_forwardنصاف Sheet Asteel bar of rectangular cross section with dimension Shown in fig. below. This bar is as Connected toawell. Using welded Join a long the sides als only find the weld size (h). Where: Tall = 35 MN/M² F=213.30 answer/h= 4.04 ☐ Yomm Soomm 100mmarrow_forwardFEAarrow_forward
- FEAarrow_forwardHELP?arrow_forwardTrue and False Indicate if each statement is true or false. T/F 1. Rule #1 protects the function of assembly. T/F 2. One of the fundamental dimensioning rules requires all dimensions apply in the free-state condition for rigid parts. T/F 3. The fundamental dimensioning rules that apply on a drawing must be listed in the general notes. T/F 4. Where Rule #1 applies to a drawing, it limits the form of every feature of size on the drawing. T/F 5. Rule #1 limits the variation between features of size on a part. T/F 6. The designer must specify on the drawing which features of size use Rule #1. T/F T/F T/F 7. Rule #1 applies to nonrigid parts (in the unrestrained state). 8. A GO gage is a fixed-limit gage. 9. Rule #1 requires that the form of an individual regular feature of size is controlled by its limits of sizearrow_forward
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