EBK ELEMENTARY SURVEYING
15th Edition
ISBN: 8220106714225
Author: GHILANI
Publisher: PEARSON
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Chapter 18, Problem 18.17P
To determine
The reason inset maps are sometimes used in maps.
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1: Determine the load capacity of the one-way uniformly loaded (5 kN/m²)
simply supported slab shown in Fig.
Solution:
2 m
2 m
هنا الاسناد بسيط، لذلك سيتشكل خط خضوع واحد
بالمنتصف ( البلاطة متناظرة)
=
We [5.0x (2x1.5) 0 = 8/2
:. W;= [m × 8/2 × 1.5] <2
= [1.5m 6]
:: We = Wi
15 6 = 1.5 m 6
m = 10 kN.m
8/2]
-8=1.0
1.5 m
E
E
L
8/2
δ
28
0 =
L/2
L
A closed tank contains compressed air and oil ( 0.90)OilS = as is shown. A U-tube manometerusing mercury ( 13.6)HgS = is connected to the tank as shown. The column heights are1 2 340 , 8 , 15h cm h cm h cm= = = . Determine the pressure reading (in KPa ) of the gage.(Answer: 15.8AirP KPa= )
A piston is placed in the right side cylinder containing 20 C water as shown in the figure.Determine the height difference ( h∆ ) in liquid surface of both sides.
Chapter 18 Solutions
EBK ELEMENTARY SURVEYING
Ch. 18 - Prob. 18.1PCh. 18 - Prob. 18.2PCh. 18 - Prob. 18.3PCh. 18 - Prob. 18.4PCh. 18 - Prob. 18.5PCh. 18 - Prob. 18.6PCh. 18 - Prob. 18.7PCh. 18 - Prob. 18.8PCh. 18 - Prob. 18.9PCh. 18 - Prob. 18.10P
Ch. 18 - Prob. 18.11PCh. 18 - Prob. 18.12PCh. 18 - Prob. 18.13PCh. 18 - Prob. 18.14PCh. 18 - Prob. 18.15PCh. 18 - Prob. 18.16PCh. 18 - Prob. 18.17PCh. 18 - Prob. 18.18PCh. 18 - Prob. 18.19PCh. 18 - Prob. 18.20PCh. 18 - Prob. 18.21PCh. 18 - Prob. 18.22PCh. 18 - Prob. 18.23PCh. 18 - Prob. 18.24PCh. 18 - Prob. 18.25PCh. 18 - Prob. 18.26PCh. 18 - Prob. 18.27PCh. 18 - Prob. 18.28PCh. 18 - Prob. 18.29PCh. 18 - Prob. 18.30PCh. 18 - Prob. 18.31P
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