a) Interpretation: The complete mechanism for the conversion of 3 0 alcohol given to 3 0 alkyl halide by treating with HCl involving two cationic intermediates is to be proposed. Concept introduction: Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide. To propose: The complete mechanism for the conversion of 3 0 alcohol given to 3 0 alkyl halide by treating with HCl involving two cationic intermediates.

Question

43) 10.00 ml of vinegar (active ingredient is acetic acid) is titrated to the endpoint using 19.32 ml of 0.250 M sodium hydroxide. What is the molarity of acetic acid in the vinegar? YOU MUST SHOW YOUR WORK. NOTE: MA x VA = MB x VB

Answer 1

Question

Chapter 17.SE, Problem 30MP

Interpretation Introduction

a)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Interpretation Introduction

b)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates.

Interpretation Introduction

c)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

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43) 10.00 ml of vinegar (active ingredient is acetic acid) is titrated to the endpoint using 19.32 ml of 0.250 M sodium hydroxide. What is the molarity of acetic acid in the vinegar? YOU MUST SHOW YOUR WORK. NOTE: MA x VA = MB x VB

424 Repon Sheet Rates of Chemical Reactions : Rate and Order of 1,0, Deception B. Effect of Temperature BATH TEMPERATURE 35'c Yol of Oh نام Time 485 Buret rend ing(n) 12 194 16. 6 18 20 10 22 24 14 115 95 14738 2158235 8:26 CMS 40148 Total volume of 0, collected Barometric pressure 770-572 ml mm Hg Vapor pressure of water at bath temperature (see Appendix L) 42.2 Slope Compared with the rate found for solution 1, there is Using the ideal gas law, calculate the moles of O; collected (show calculations) times faster 10 Based on the moles of O, evolved, calculate the molar concentration of the original 3% 1,0, solution (sho calculations)

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Answer 2

Question

Chapter 17.SE, Problem 30MP

Interpretation Introduction

a)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Interpretation Introduction

b)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates.

Interpretation Introduction

c)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

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Answer 3

Question

Chapter 17.SE, Problem 30MP

Interpretation Introduction

a)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Interpretation Introduction

b)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates.

Interpretation Introduction

c)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

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Answer 4

Question

Chapter 17.SE, Problem 30MP

Interpretation Introduction

a)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Interpretation Introduction

b)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates.

Interpretation Introduction

c)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

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Answer 5

Chapter 17.SE, Problem 30MP

Interpretation Introduction

a)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Interpretation Introduction

b)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates.

Interpretation Introduction

c)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Answer 6

Chapter 17.SE, Problem 30MP

Interpretation Introduction

a)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Answer 7

Chapter 17.SE, Problem 30MP

Interpretation Introduction

a)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Answer 8

Interpretation Introduction

b)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates.

Answer 9

Interpretation Introduction

b)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HBr involving two cationic intermediates.

Answer 10

Interpretation Introduction

c)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Answer 11

Interpretation Introduction

c)

Interpretation:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates is to be proposed.

Concept introduction:

Alcohols get protonated in the presence of strong acids. The protonated intermediate will lose a molecule of water to yield a carbocation. The nucleophilic attack by the halide ion will lead to the formation of the alkyl halide.

To propose:

The complete mechanism for the conversion of 3⁰ alcohol given to 3⁰ alkyl halide by treating with HCl involving two cationic intermediates.

Answer 12

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Answer 23

Ch. 17.1 - Give IUPAC names for the following compounds:Ch. 17.1 - Prob. 2P Ch. 17.2 - The following data for isomeric four-carbon...Ch. 17.2 - Rank the following substances in order of...Ch. 17.2 - Prob. 5P Ch. 17.3 - Prob. 6P Ch. 17.4 - What reagent would you use to accomplish each of...Ch. 17.4 - Prob. 8P Ch. 17.5 - Prob. 9P Ch. 17.5 - Prob. 10P

Solution Summary: The author proposes the complete mechanism for the conversion of 3 0 alcohol given to 3 1 alkyl halide by treating with HCl.

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Chapter 17 Solutions