Explanation Given: Each type of calculator assembled in two set of operations and timing for each operation is 8 h. In first operation, the average time required for business calculator is 3 min, in second operation required time is 6 min. In first operation, the average time required for graphing calculator is 6 min, in second operation required time is 4 min. The profit of business calculator is $8 and graphing calculator is $10. Calculation: Let x be the number of business calculator produced and y be the number of graphing calculator produced. By the given information, the objective function can be P = 8 x + 10 y . Convert the timing for each operation as 8 × 60 = 480 min . And subject to the constraints of the problem is, 3 x + 6 y ≤ 480 6 x + 4 y ≤ 480 x ≥ 0 , y ≥ 0 Calculation: Draw the graph of the inequality as shown in below Figure 1. From Figure 1, it is observed that the feasible points are ( 0 , 0 ) , ( 0 , 80 ) , ( 80 , 0 ) and ( 40 , 60 ) which is in the shaded region including the line segments on the edges satisfies all the constraints. Obtain the maximum value of P by using the feasible points as shown in below table

11th Edition

ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 17.6, Problem 19E

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To find: The number of business type calculator and graphing calculator will produce per day in order to maximize profit.

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Chapter 17.6, Problem 18E

Chapter 17.6, Problem 20E

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Chapter 17 Solutions

Basic Technical Mathematics

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