Chapter 17.6, Problem 17.15AFP

(a)

Interpretation Introduction

Interpretation : The $K_p$ value for the given reaction mixture should be calculated.

  $C_{2(g)}+D_{2(g)}\rightleftharpoons 2C{D}_{(g)}\Delta H<0$

  

Concept Introduction : $K_{\text{p}}$ is an equilibrium constant in terms of partial pressure. Consider an equilibrium reaction as follows:

  $A +B \rightleftharpoons C+D$

Expression for the equilibrium constant is as follows:

  $K_{\text{p}}=\frac{[PC][PD]}{[PA][PB]}$

Here, $P$ represents the partial pressure.

(b )

Interpretation Introduction

Interpretation : The direction of the reaction should be interpreted when the reaction is not at equilibrium.

  $C_2\left(g\right)+D_2\left(g\right)\rightleftharpoons 2CD\left(g\right)\Delta H<0$

  

Concept Introduction : $K_{\text{p}}$ is an equilibrium constant in terms of partial pressure. Consider an equilibrium reaction as follows:

  $A +B \rightleftharpoons C+D$

Expression for equilibrium constant is as follows:

  $K_{\text{p}}=\frac{[PC][PD]}{[PA][PB]}$

(c)

Interpretation Introduction

Interpretation : The effect of the rise in the T on the amount of product should be interpreted when the reaction is at equilibrium.

  $C_{2(g)}+D_{2(g)}\rightleftharpoons 2C{D}_{(g)}\Delta H<0$

  

Concept Introduction: $K_{\text{p}}$ is an equilibrium constant in terms of partial pressure. Consider an equilibrium reaction as follows:

  $A +B \rightleftharpoons C+D$

Expression for equilibrium constant is as follows:

  $K_{\text{p}}=\frac{[PC][PD]}{[PA][PB]}$