Explanation Given: 1) A current i at time t which is producing magnetic field B is defined by following formula i ( t ) = 10 e − 0.1 t 2) Magnitude of produced magnetic field B is as follows B = μ 0 i 2 π r T Where μ 0 = 4 π × 10 − 7 T − m / A i = current passing through the wire r = distance of magnetic field from wire 3) The area through which the flux needs to be calculated is the isosceles triangle of base 12cm and height 6cm, whose bottom edge is 3cm from the wire. 4) Given figure is follows Formula used: 1) Flux of magnetic field is given by ϕ = ∬ S F . d S 2) Faraday’s law states that voltage drop around the closed surface can be determine by differentiation of flux with respect to time is Voltage drop = d ϕ d t 3) If A = ( x 1 , y 1 ) and B = ( x 2 , y 2 ) then equation of line A B is x − x 1 x 2 − x 1 = y − y 1 y 2 − y 1 Calculation: Flux ϕ ( t ) = ∬ S B . d S [using formula ϕ = ∬ S F . d S ] B = μ 0 i 2 π r [given] Area through which the flux needs to be calculated is isosceles triangle having base 12cm and height is 6cm. Assuming the wire is on x -axis following diagram is simplified version of fig 17 to get the characteristics of flux area Calculating equation of line OB and BA which will be use in further calculation, Equation of line OB is x − 0 6 − 0 = y − 3 9 − 3 [using formula x − x 1 x 2 − x 1 = y − y 1 y 2 − y 1 ] x 6 = y − 3 6 x + 3 = y Equation of line BA is x − 6 12 − 6 = y − 9 3 − 9 [using formula x − x 1 x 2 − x 1 = y − y 1 y 2 − y 1 ] x − 6 6 = y − 9 − 6 x + y = 15 Consider a strip on a triangle OAB, which is parallel to x -axis ϕ ( t ) = ∬ S B ...

4th Edition

ISBN: 9781319055844

Author: FRANZOSA

Publisher: VST

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Chapter 17.5, Problem 33E

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The flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday’s law.

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Chapter 17.5, Problem 32E

Chapter 17.5, Problem 34E

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Chapter 17 Solutions

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The flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday’s law.

Solution Summary: The author calculates the flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday's law.

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To Calculate: The flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday’s law.

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Chapter 17 Solutions

To Calculate:

The flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday’s law.