Green’s Theorem as a Fundamental Theorem of Calculus Show that if the circulation form of Green’s Theorem is applied to the vector field 〈 0 , f ( x ) c 〉 and R = { ( x , y ) : a ≤ x ≤ b , 0 ≤ y ≤ c } , then the result is the Fundamental Theorem of Calculus, ∫ a b d f d x d x = f ( b ) − f ( a ) .
Green’s Theorem as a Fundamental Theorem of Calculus Show that if the circulation form of Green’s Theorem is applied to the vector field 〈 0 , f ( x ) c 〉 and R = { ( x , y ) : a ≤ x ≤ b , 0 ≤ y ≤ c } , then the result is the Fundamental Theorem of Calculus, ∫ a b d f d x d x = f ( b ) − f ( a ) .
Solution Summary: The author explains that if the circulation form of Green's theorem is applied to the vector field langle 0,f(x)crangle and R=left
Green’s Theorem as a Fundamental Theorem of Calculus
Show that if the circulation form of Green’s Theorem is applied to the vector field
〈
0
,
f
(
x
)
c
〉
and
R
=
{
(
x
,
y
)
:
a
≤
x
≤
b
,
0
≤
y
≤
c
}
, then the result is the Fundamental Theorem of Calculus,
∫
a
b
d
f
d
x
d
x
=
f
(
b
)
−
f
(
a
)
.
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
According to Newton's law of universal gravitation, the force F between two bodies of constant mass
GmM
m and M is given by the formula F =
, where G is the gravitational constant and d is the
d²
distance between the bodies.
a. Suppose that G, m, and M are constants. Find the rate of change of force F with respect to
distance d.
F' (d)
2GmM
b. Find the rate of change of force F with gravitational constant G = 6.67 × 10-¹¹ Nm²/kg², on
two bodies 5 meters apart, each with a mass of 250 kilograms. Answer in scientific notation,
rounding to 2 decimal places.
-6.67x10
N/m syntax incomplete.
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