Electrical Motor Controls for Integrated Systems
5th Edition
ISBN: 9780826912268
Author: Gary Rockis;Glen A. Mazur
Publisher: American Technical Publishers
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Chapter 17.3, Problem 1CP
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To explain: What determines the amount of braking force that is applied to the motor in the electric braking method.
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Q6 The FET shown in Fig. 1.43 has gm = 3.4 mS and rd =100 K. Find the approximate
lower cutoff frequency. Ans: 735.1 Hz.
25V
1.5ΜΩ
20 ΚΩ
0.02µF
HH
2ΚΩ
0.02µF
HH
330kQ
820 ΩΣ
1.0µF
www
40ΚΩ
The solution is with a pen and paper, without artificial intelligence.
Q5 For the network of Fig. 1.42; determine re, Avmid, Zi, Avsmid, and the low cutoff frequency.
Ans: 30.23 2; 0.983; 21.13 KS; 0.955; 193.16 Hz.
14V
+
Vs
1 ΚΩ
0.1 µF
Vi
120 ΚΩ
B-100
0.1 µF
o Vo
30 ΚΩ
32.2 ΚΩ
18.2 ΚΩ
Fig. 1.42 Circuit for Q5.
31
Chapter 17 Solutions
Electrical Motor Controls for Integrated Systems
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- Q1) (a) State Biot-Savart's law (b) The y- and z-axes, respectively, carry filamentary currents 10 A along ay and 20 A along -az. Find H at (- 3, 4, 5).arrow_forwardQ5) a) State Ampere's circuit law. b) In a certain conducting region, H = yz(x² + y²)ax - y²xzay + 4x²y²a, A/m. (a) Determine J at (5, 2, -3) (b) Find the current passing through x = -1, 0 < y, z <2 (c) Show that V⚫H=0arrow_forwardFig. 1.43 Circuit for Q6- Q7 For the network of Fig. 1.44: a-Determine fH; and fHo b- Find fg and fr. c- Sketch the frequency response for the high-frequency region using a Bode plot and determine the cutoff frequency. Ans: 277.89 KHz; 2.73 MHz; 895.56 KHz; 107.47 MHz. 14V Cw=5pF Cbc-12 pF Cwo-8pF Che=40. pF 5.6kQ C-8pF 68kQ 0.47µF ww 0.82 kQ V₁ 0.47uF AN B=120 3.3kQ 10ΚΩ 1.2k0 =20µF Fig. 1.44 Circuit for Q7.arrow_forward
- Q3) An infinite long filamentary wire carries a current of 2A in the +z direction. calculate: (a)B at (-3,4,7) (b) the flux through the square loop described by 25 16,0 Sz≤4, 0=90°.arrow_forwardQ3) An infinitely long conductor is bent into an L shape as shown in Figure below. If a direct current of 5 A flows in the current, find the magnetic field intensity at (2, 2, 0). 5 A 5 Aarrow_forwardEx. 1° let Ĥ = -y (x²+y^³) ax + x (x²+y"`) ây":" H 5 find J M total current Passing through Z=oplane with the rectangular -\-2<<2arrow_forward
- Q) Given the magnetic field vector potential: A= y² za, +2(x+1)y z ay- (x+1) z² az (A/m), find: (1)magnetic flux density B, (2)magnetic field intensity H, (3) current density J and (4) the current passing through surface y = 1,0≤x≤1, 0 ≤z≤1.arrow_forwardQ9 For the network of Fig. 1.46: a- Determine gmo and gm. b- Find A, and Ay, in the mid-frequency range. c- Determine fH; and fHo Ans: 3.33 mS; 1.91 mS; -4.39; -4.27; 1.84 MHz; 3.68 MHz. + 1.5 kQ 20V 3220ΚΩ 1µF 68kQ AN CwF4pF Co=8 pF Cwo=6pF Cgs=12pF 53.9ΚΩ Cds=3pF 6.8µF o Vo Dss=10mA Vp=-6V 15.6 ΚΩ 2.2k =10µF Fiarrow_forwardQs For the network of Fig. 1.45: a- Determine fH, and fHo b- Find fp and fr c- Sketch the frequency response for the high-frequency region using a Bode plot and determine the cutoff frequency. Ans: 2.87 MHz, 185.78 MHz, 1.05 MHz, 105 MHz. 14V CWF8pF Cwo-10pF Cbc-20 pF Cbe=30pF 120 ΚΩ Co=12pF 1 ΚΩ B-100 0.1 µF Vs 0.1 HF Z; Vo www 30 kQ 2.2 ΚΩ € 8.2 kQ Fig. 1.45 Circuit for Carrow_forward
- 5 A Q4) A thin ring of radius 5 cm is placed on plane z = 1 cm so that its center is at (0,0,1 cm). If the ring carries 50 mA along a^, find H at (0,0,a).arrow_forwardQ6) Find the current density J for the magnetic field intensity vectors: (a) H = x²ya, + y²zay - 2xza, (b) H = p²zap + p³a + 3pz²az sin cos (c) H = a, 2 +2arrow_forwardQ2) Line x = 0, y=0,0arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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