
Concept explainers
(a)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction:
The hydrocarbon compounds are the compound containing only hydrogen and carbon atoms, compounds that contain carbon-carbon multiple bond(s) are said to be
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkene, the suffix “ane” of the corresponding
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
(b)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction:
The hydrocarbon compounds are the compound containing only hydrogen and carbon atoms, compounds that contain carbon-carbon multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
(c)
Interpretation: The IUPAC name of the following compound should be determined:
Concept Introduction:
The hydrocarbon compounds are the compound containing only hydrogen and carbon atoms, compounds that contain carbon-carbon multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.
In order to give the name to the unsaturated hydrocarbon following steps are followed:
1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.
2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.
3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec

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Chapter 17 Solutions
EP BASIC CHEMISTRY-STANDALONE ACCESS
- 3) Label the configuration in each of the following alkenes as E, Z, or N/A (for non-stereogenic centers). 00 E 000 N/A E Br N/A N/A (g) E N/A OH E (b) Oz N/A Br (d) 00 E Z N/A E (f) Oz N/A E (h) Z N/Aarrow_forward6) Fill in the missing Acid, pKa value, or conjugate base in the table below: Acid HCI Approximate pK, -7 Conjugate Base H-C: Hydronium (H₂O') -1.75 H-O-H Carboxylic Acids (RCOOH) Ammonium (NH4) 9.24 Water (H₂O) H-O-H Alcohols (ROH) RO-H Alkynes R--H Amines 25 25 38 HOarrow_forward5) Rank the following sets of compounds in order of decreasing acidity (most acidic to least acidic), and choose the justification(s) for each ranking. (a) OH V SH я вон CH most acidic (lowst pKa) least acidic (highest pKa) Effect(s) Effect(s) Effect(s) inductive effect O inductive effect O inductive effect electronegativity electronegativity O electronegativity resonance polarizability resonance polarizability O resonance O polarizability hybridization Ohybridization O hybridization оarrow_forward
- How negatively charged organic bases are formed.arrow_forwardNonearrow_forward1) For the following molecules: (i) Label the indicated alkenes as either cis (Z), trans (E), or N/A (for non-stereogenic centers) by bubbling in the appropriate label on the molecule. (ii) Complete the IUPAC name located below the structure (HINT: Put the letter of the configuration in parentheses at the beginning of the name!) E z N/A ()-3,4,6-trimethylhept-2-ene E Oz O N/A ()-3-ethyl-1-fluoro-4-methylhex-3-ene E -+- N/A Me )-2,3-dimethylpent-2-ene (d) (b) E O N/A Br ()-5-bromo-1-chloro-3-ethyloct-4-ene ОЕ Z N/A Et (___)-3-ethyl-4-methylhex-3-ene E (f) Oz N/A z N/A HO (4.7)-4-(2-hydroxyethyl)-7-methylnona-4,7-dien-2-onearrow_forward
- O 9:21AM Tue Mar 4 ## 64% Problem 51 of 15 Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. H :0: CI. AI :CI: :CI: Cl AI Select to Add Arrows Select to Add Arrows O: Cl :CI: :0: H CI: CI CO Select to Add Arrows Select to Add Arrows :O: CI :0: Cl. 10: AIarrow_forward(i) Draw in the missing lone pair(s) of electrons of the reactants on the left (ii) Draw (curved) arrows to show the flow of electrons in the acid/base reaction on the left (iii) Draw the products of the acid/base on the right (iv) Select the correct label for each product as either "conjugate acid" or "conjugate base" (a) JOH OH NH₂ acid base (b) De "H conjugate acid conjugate acid conjugate base conjugate base acid base conjugate acid conjugate base conjugate acid conjugate base acid basearrow_forwardCould someone answer this NMR and explain please Comment on the general features of the 1H-NMR spectrum of isoamyl ester provided below.arrow_forward
- Macmillan Learning Draw the acyl chloride that would give the ketone shown using the Friedel-Crafts acylation reaction. Select Draw Templates More с H о Cl 2Q Erase AICI₂arrow_forwardDraw the complete mechanism for this reaction: .OH مدید OH H2SO4 + H₂O To save you some time, the starting material has been copied into the first drawing area. However, you will still need to add any other reactants or catalysts that take part in the reaction. ན ི.. OH Add/Remove step Х ด ك Click and drag to start drawing a structure.arrow_forward9:27 AM Tue Mar 4 ← Problem 64 of 15 #63% Submit Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. 0:0 0:0 :0: N. :0: :O :0: H H. :0: Select to Add Arrows O :0: H O :0: 0:0. S. H Select to Add Arrows S :0: :0: H Harrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
