Electric field due to a point charge The electric field in the xy -plane due to a point charge at (0,0) is a gradient field with a potential function V ( x , y ) = k x 2 + y 2 where k > 0 is a physical constant. a. Find the components of the electric field in the x -and y -directions, where E ( x , y ) = − ∇ Δ ( x , y ) b. Show that the vectors of the electric field point in the radial direction (outward from the origin) and the radial component of E can be expressed as E r = k/r 2 , where x 2 + y 2 . c. Show that the vector field is orthogonal to the equipotential curves at all points in the domain of V
Electric field due to a point charge The electric field in the xy -plane due to a point charge at (0,0) is a gradient field with a potential function V ( x , y ) = k x 2 + y 2 where k > 0 is a physical constant. a. Find the components of the electric field in the x -and y -directions, where E ( x , y ) = − ∇ Δ ( x , y ) b. Show that the vectors of the electric field point in the radial direction (outward from the origin) and the radial component of E can be expressed as E r = k/r 2 , where x 2 + y 2 . c. Show that the vector field is orthogonal to the equipotential curves at all points in the domain of V
Solution Summary: The author calculates the gradient field of the potential function V(x,y)=ksqrtx2+y2.
Electric field due to a point charge The electric field in the xy-plane due to a point charge at (0,0) is a gradient field with a potential function
V
(
x
,
y
)
=
k
x
2
+
y
2
where k > 0 is a physical constant.
a. Find the components of the electric field in the x-and y-directions, where
E
(
x
,
y
)
=
−
∇
Δ
(
x
,
y
)
b. Show that the vectors of the electric field point in the radial direction (outward from the origin) and the radial component of E can be expressed as Er = k/r2, where
x
2
+
y
2
.
c. Show that the vector field is orthogonal to the equipotential curves at all points in the domain of V
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
4. Use method of separation of variable to solve the following wave equation
მłu
J²u
subject to
u(0,t) =0, for t> 0,
u(л,t) = 0, for t> 0,
=
t> 0,
at²
ax²'
u(x, 0) = 0,
0.01 x,
ut(x, 0) =
Π
0.01 (π-x),
0
Solve the following heat equation by method of separation variables:
ди
=
at
subject to
u(0,t) =0, for
-16024
ძx2 •
t>0, 0 0,
ux (4,t) = 0, for
t> 0,
u(x, 0) =
(x-3,
\-1,
0 < x ≤2
2≤ x ≤ 4.
ex
5.
important aspects.
Graph f(x)=lnx. Be sure to make your graph big enough to easily read (use the space given.) Label all
6
33
Chapter 17 Solutions
MyLab Math with Pearson eText -- Standalone Access Card -- for Calculus: Early Transcendentals (3rd Edition)
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