a) (Z)-2-Ethyl-2-buten-1-ol Interpretation: To draw the structure of (Z)-2-ethyl-2-buten-1-ol. Concept introduction: The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group. E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned. To draw: The structure of (Z)-2-ethyl-2-buten-1-ol.

Question

The table includes macrostates characterized by 4 energy levels (&) that are equally spaced but with different degrees of occupation. a) Calculate the energy of all the macrostates (in joules). See if they all have the same energy and number of particles. b) Calculate the macrostate that is most likely to exist. For this macrostate, show that the population of the levels is consistent with the Boltzmann distribution. macrostate 1 macrostate 2 macrostate 3 ε/k (K) Populations Populations Populations 300 5 3 4 200 7 9 8 100 15 17 16 0 33 31 32 DATO: k = 1,38×10-23 J K-1

Answer 1

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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The table includes macrostates characterized by 4 energy levels (&) that are equally spaced but with different degrees of occupation. a) Calculate the energy of all the macrostates (in joules). See if they all have the same energy and number of particles. b) Calculate the macrostate that is most likely to exist. For this macrostate, show that the population of the levels is consistent with the Boltzmann distribution. macrostate 1 macrostate 2 macrostate 3 ε/k (K) Populations Populations Populations 300 5 3 4 200 7 9 8 100 15 17 16 0 33 31 32 DATO: k = 1,38×10-23 J K-1

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In an experiment, the viscosity of water was measured at different temperatures and the table was constructed from the data obtained. a) Calculate the activation energy of viscous flow (kJ/mol). b) Calculate the viscosity at 30°C. T/°C 0 20 40 60 80 η/cpoise 1,972 1,005 0,656 0,469 0,356

Answer 2

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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Answer 3

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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Answer 4

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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Answer 5

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

Answer 6

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Answer 7

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Answer 8

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Answer 9

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Answer 10

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Answer 11

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Answer 12

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Answer 13

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Answer 14

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Answer 15

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Answer 16

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

Answer 17

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

Answer 18

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Ch. 17.1 - Give IUPAC names for the following compounds:Ch. 17.1 - Prob. 2P Ch. 17.2 - The following data for isomeric four-carbon...Ch. 17.2 - Rank the following substances in order of...Ch. 17.2 - Prob. 5P Ch. 17.3 - Prob. 6P Ch. 17.4 - What reagent would you use to accomplish each of...Ch. 17.4 - Prob. 8P Ch. 17.5 - Prob. 9P Ch. 17.5 - Prob. 10P

Chapter 17 Solutions