a) (Z)-2-Ethyl-2-buten-1-ol Interpretation: To draw the structure of (Z)-2-ethyl-2-buten-1-ol. Concept introduction: The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group. E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned. To draw: The structure of (Z)-2-ethyl-2-buten-1-ol.

Question

For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HE

Answer 1

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HE

Predicting As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C - C bond as its major product: H₂N O H 1. ? 2. H3O+ If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. 0 If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. فا Explanation Check Click and drag to start drawing a structure.

Highlight the chirality (or stereogenic) center(s) in the given compound. A compound may have one or more stereogenic centers. OH OH OH OH OH OH

Answer 2

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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Answer 3

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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Answer 4

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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Answer 5

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

Answer 6

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Answer 7

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Answer 8

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Answer 9

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Answer 10

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Answer 11

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Answer 12

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Answer 13

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Answer 14

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Answer 15

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Answer 16

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

Answer 17

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

Answer 18

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Answer 19

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Answer 29

Ch. 17.1 - Give IUPAC names for the following compounds:Ch. 17.1 - Prob. 2P Ch. 17.2 - The following data for isomeric four-carbon...Ch. 17.2 - Rank the following substances in order of...Ch. 17.2 - Prob. 5P Ch. 17.3 - Prob. 6P Ch. 17.4 - What reagent would you use to accomplish each of...Ch. 17.4 - Prob. 8P Ch. 17.5 - Prob. 9P Ch. 17.5 - Prob. 10P

Chapter 17 Solutions