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(a)
Interpretation:
The name of the given compound should be determined.
Concept Introduction:
In order to give the IUPAC name to the
1. The parent (longest) continuous carbon chain is identified.
2. The ending of the parent chain for alkane (-e) is -ane.
3. Name should be written in alphabetical order and numbering should be done in such a way that the substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
(b)
Interpretation:
The name of the given compound should be determined.
Concept Introduction:
In order to give the IUPAC name to the branched-chain alkane following steps are followed:
1. The parent (longest) continuous carbon chain is identified.
2. The ending of the parent chain for alkane (-e) is -ane.
3. Name should be written in alphabetical order and numbering should be done in such a way that the substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
(c)
Interpretation:
The name of the given compound should be determined.
Concept Introduction:
In order to give the IUPAC name to the branched-chain alkane following steps are followed:
1. The parent (longest) continuous carbon chain is identified.
2. The ending of the parent chain for alkane (-e) is -ane.
3. Name should be written in alphabetical order and numbering should be done in such a way that the substituent group gets lowest number.
4. Hyphen is used to connect the number to the name.
For number of carbons atoms in alkane chain, the prefix is given as:
Carbon-1 meth
Carbon-2 eth
Carbon-3 prop
Carbon-4 but
Carbon-5 pent
Carbon-6 hex
Carbon-7 hept
Carbon-8 oct
Carbon-9 non
Carbon-10 dec
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Chapter 17 Solutions
EBK BASIC CHEMISTRY
- The azide ion is N3^-. In addition to the ionic charge, it’s three mostimportant contributing structures also have formal charges. The totalnumber of π bonds in these three contributing structures isA. 6; B. 12; C. 3; D. 9; E. None of the other answers is correct.arrow_forwardThe sum of the numerals in the name of the compoundis A. None of the other answers is correct.; B. 11;C. 6; D. 8; E. 5.arrow_forwardA compound has a six carbon ring with three double bonds. Attachedto the ring is a three carbon chain with a triple bond and a two carbonchain with two bromines attached. The number of hydrogens in a molecule of this compound is A. 10; B. 12; C. 14; D. 13; E. None of the other answers is correct.arrow_forward
- Can you help me? I can't seem to understand the handwriting for the five problems, and I want to be able to solve them and practice. If you'd like to give me steps, please do so to make it easier understand.arrow_forwardThe number of 2sp3 hybrid orbitals in the moleculeis A. 12; B. 8; C. 3; D. 11; E. None of the other answers is correct.arrow_forwardNonearrow_forward
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