Chapter 17, Problem 91E

Interpretation Introduction

Interpretation: The molar mass of compound that is 0.500 g of sample dissolved in 100.0 mL of solution and exhibits 2.50 atm osmotic pressure needs to be determined, if each molecule of solute dissociate into two particles.

Concept Introduction: Colligative properties are the properties of solution which depend on the number of particles present in the solution. Some common examples of colligative properties are depression in freezing point, elevation in boiling point, osmotic pressure, lowering in vapor pressure, etc. The number of particles is shown with the help of Van’t Hoff factor ‘i’.

The mathematical expression for osmotic pressure is as given below:

  $\begin{array}{l}\text{π = }i\times \text{C × R ×T}\\ \text{π = osmotic pressure}\\ \text{C = concentration}\\ \text{R= universal gas constant}\\ \text{T = temperature}\end{array}$