COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 17, Problem 90QAP
To determine

(a)

The electric potential energy of the charge distribution

Expert Solution
Check Mark

Answer to Problem 90QAP

Potential energy of the charge distribution is =3Kq2a

Explanation of Solution

Given:

Side of a rhombus is a
Short diagonal is length a and long diagonal is of length b
Calculation:

Potential energy of the charge distribution is
  Utotal=Uq1q2+Uq2q3+Uq1q3=Kq1q2a+Kq2q3a+Kq1q3a=Ka[q1q2+q2q3+q1q3]=Ka[q2+q2+q2]=3Kq2a

Conclusion:

Potential energy of the charge distribution is =3Kq2a

To determine

(b)

The potential energy at the vacant end of the rhombus

Expert Solution
Check Mark

Answer to Problem 90QAP

The work required to bring the fourth particle =Kq2a(13+2)

Explanation of Solution

The potential energy at the vacant end of the rhombus is zero

To determine

(c)

To calculate the work required to bring the fourth particle

Expert Solution
Check Mark

Answer to Problem 90QAP

The work required to bring the fourth particle =Kq2a(13+2)

Explanation of Solution

Given:

Side of a rhombus is a
Short diagonal is length a and long diagonal is of length b
Calculation:

  W=ΔU=UfUi=Uf0=Uq1q4+Uq2q4+Uq3q4=Kq1q2b+Kq2q3a+Kq1q3a=Kq1q2 3 a 2 +Kq2q3a+Kq1q3a=Kq23a+2Kq2a=Kq2a(1 3 +2)

Conclusion:

The work required to bring the fourth particle =Kq2a(13+2)

To determine

(d)

The total potential energy of four charges

Expert Solution
Check Mark

Answer to Problem 90QAP

The total potential energy of four charges =Kq2a(13+5)

Explanation of Solution

Given:

Side of a rhombus is a
Short diagonal is length a and long diagonal is of length b
Calculation:

  Utotal=Uq1q2+Uq2q3+Uq1q3+Uq1q4+Uq2q4+Uq3q4=3Kq2a+Kq2a(1 3 +2)=Kq2a(1 3 +5)

Conclusion:

The total potential energy of four charges =Kq2a(13+5)

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Chapter 17 Solutions

COLLEGE PHYSICS

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