GO Hot chocolate effect . Tap a metal spoon inside a mug of water and note the frequency f i you hear. Then add a spoonful of powder (say, chocolate mix or instant coffee) and tap again as you stir the powder. The frequency you hear has a lower value f s because the tiny air bubbles released by the powder change the water’s bulk modulus. As the bubbles reach the water surface and disappear, the frequency gradually shifts back to its initial value. During the effect, the bubbles don’t appreciably change the water’s density or volume or the sound’s wavelength. Rather, they change the value of dV/dp— that is, the differential change in volume due to the differential change in the pressure caused by the sound wave in the water. If f s / f i = 0.333, what is the ratio ( dV / dp ) s /( dV / dp ) i ?
GO Hot chocolate effect . Tap a metal spoon inside a mug of water and note the frequency f i you hear. Then add a spoonful of powder (say, chocolate mix or instant coffee) and tap again as you stir the powder. The frequency you hear has a lower value f s because the tiny air bubbles released by the powder change the water’s bulk modulus. As the bubbles reach the water surface and disappear, the frequency gradually shifts back to its initial value. During the effect, the bubbles don’t appreciably change the water’s density or volume or the sound’s wavelength. Rather, they change the value of dV/dp— that is, the differential change in volume due to the differential change in the pressure caused by the sound wave in the water. If f s / f i = 0.333, what is the ratio ( dV / dp ) s /( dV / dp ) i ?
GOHot chocolate effect. Tap a metal spoon inside a mug of water and note the frequency fi you hear. Then add a spoonful of powder (say, chocolate mix or instant coffee) and tap again as you stir the powder. The frequency you hear has a lower value fs because the tiny air bubbles released by the powder change the water’s bulk modulus. As the bubbles reach the water surface and disappear, the frequency gradually shifts back to its initial value. During the effect, the bubbles don’t appreciably change the water’s density or volume or the sound’s wavelength. Rather, they change the value of dV/dp—that is, the differential change in volume due to the differential change in the pressure caused by the sound wave in the water. If fs/fi = 0.333, what is the ratio (dV/dp)s/(dV/dp)i?
suggest a reason ultrasound cleaning is better than cleaning by hand?
Checkpoint 4
The figure shows four orientations of an electric di-
pole in an external electric field. Rank the orienta-
tions according to (a) the magnitude of the torque
on the dipole and (b) the potential energy of the di-
pole, greatest first.
(1)
(2)
E
(4)
What is integrated science.
What is fractional distillation
What is simple distillation
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