Explanation A. 8.7×10 -3 M LiOH As we know that LiOH is a strong base, it completely ionizes and gives 1 ion. [OH - ] = 8.7×10 -3 [H 3 O + ][OH - ] = 1.0×10 -14 M [ H3O + ] = 1 .0×10 -14 8 .7×10 -3 M =1.1×10 -12 M pOH=-log[OH - ] =-log(8.7×10 -3 ) =2.06 B. 0.0112 M Ba(OH) 2 As we know that, barium hydroxide is a strong base it gives two ions after complete ionization. [OH - ] = 2×0.0112M = 0.0224M [H 3 O + ][OH - ] = 1.0×10 -14 [ H3O + ] = 1 .0×10 -14 0 .0224M =4.46×10 -13 M pOH=-log[OH - ] =-log(0.00224) =1.65 C. 1.9×10 -4 M KOH KOHis a strong base and it gives ions after complete ionization. [OH - ] = 1.9×10 -4 M = [H 3 O + ][OH - ] = 1.0×10 -14 [ H3O + ] = 1 ...

Chemistry: Structure and Properties Custom Edition for Rutgers University General Chemistry

15th Edition

ISBN: 9781269935678

Author: Nivaldo J. Tro

Publisher: Pearson Education

See similar textbooks

Concept explainers

Ionic Equilibrium

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibri…

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.

Videos

Question

Chapter 17, Problem 84E

Interpretation Introduction

To determine:

For each strong base solution, determine [OH^-], [H₃O⁺], andpOH.

A, 8.7×10^-3 M LiON

B, 0.0112 M Ba(OH)₂

C, 1.9×10^-4 M KOH

D, 5.0×10^-4 M Ca(OH)²

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 17, Problem 83E

Chapter 17, Problem 85E

Chapter 17 Solutions

Chemistry: Structure and Properties Custom Edition for Rutgers University General Chemistry

Ch. 17 - Identify the conjugate base in the reaction shown...Ch. 17 - Which pair is a Bronsted-Lowry conjugate acid-base...Ch. 17 - Which acid has the largest Ka: HClO2(aq),...Ch. 17 - Consider the given acid ionization constants and...Ch. 17 - What is the OH- concentration in an aqueous...Ch. 17 - An HNO3(aq) solution has a pH of 1.75. What is the...Ch. 17 - Find the pH of a 0.350 M aqueous benzoic acid...Ch. 17 - Find the pH of a 0.155 M HClO2(aq) solution. For...Ch. 17 - 9. Calculate the percent ionization of 1.45 M...Ch. 17 - Consider two aqueous solutions of nitrous acid...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

For each strong base solution, determine [OH - ], [H 3 O + ], andpOH. A, 8.7×10 -3 M LiON B, 0.0112 M Ba(OH) 2 C, 1.9×10 -4 M KOH D, 5.0×10 -4 M Ca(OH) 2

Solution Summary: The author explains that LiOH is a strong base that completely ionizes and gives 1 ions.

Concept explainers

Videos

To determine:

For each strong base solution, determine [OH^-], [H₃O⁺], andpOH.

A, 8.7×10^-3 M LiON

B, 0.0112 M Ba(OH)₂

C, 1.9×10^-4 M KOH

D, 5.0×10^-4 M Ca(OH)²

Want to see the full answer?

Chapter 17 Solutions

For each strong base solution, determine [OH - ], [H 3 O + ], andpOH. A, 8.7×10 -3 M LiON B, 0.0112 M Ba(OH) 2 C, 1.9×10 -4 M KOH D, 5.0×10 -4 M Ca(OH) 2

Solution Summary: The author explains that LiOH is a strong base that completely ionizes and gives 1 ions.

Concept explainers

Videos

To determine: For each strong base solution, determine [OH-], [H3O+], andpOH. A, 8.7×10-3 M LiON B, 0.0112 M Ba(OH)2 C, 1.9×10-4 M KOH D, 5.0×10-4 M Ca(OH)2

Want to see the full answer?

Chapter 17 Solutions

To determine:

For each strong base solution, determine [OH^-], [H₃O⁺], andpOH.

A, 8.7×10^-3 M LiON

B, 0.0112 M Ba(OH)₂

C, 1.9×10^-4 M KOH

D, 5.0×10^-4 M Ca(OH)²