(a) Explanation The distance between the Earth’s surface and the thundercloud is 550 m and the base dimension of the cloud is 4.5 km by 2.5 km . The base of the thunder cloud acts as the positive plate in the capacitor and the Earth’s surface acts as the negative plate. Write the expression for capacitance of a parallel plate capacitor C = ∈ 0 A d (I) Here, ∈ 0 is the permittivity of free space, A is the area of the capacitor and d is the distance between the Earth’s surface and the thundercloud. Substitute 8.85 × 10 − 12 N − 1 C 2 m − 2 for ∈ 0 , 550 m for d and 4.5 km × 2 .5 km for A in (I) to find C C = ( 8 (b) To determine The energy stored in the capacitor with thundercloud and the Earth’s surface as the parallel plates.

5th Edition

ISBN: 9781260487008

Author: GIAMBATTISTA, Alan

Publisher: MCGRAW-HILL HIGHER EDUCATION

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Chapter 17, Problem 81P

(a)

To determine

The capacitance of the thundercloud.

(b)

To determine

The energy stored in the capacitor with thundercloud and the Earth’s surface as the parallel plates.

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Chapter 17, Problem 80P

Chapter 17, Problem 82P

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