Whether the electric field do positive or negative work when the charge − q moves closer to + Q .

Question

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Answer 1

Question

Chapter 17, Problem 1CQ

(a)

To determine

Whether the electric field do positive or negative work when the charge −q moves closer to +Q.

(a)

Expert Solution

Answer to Problem 1CQ

The electric field does positive work when the charge −q moves closer to +Q.

Explanation of Solution

When we move two opposite charges close together, their initial and final kinetic energies will be zero, so the external force does negative work and the electric field does positive work.

Write the expression for the external work.

Wext=ΔU=−Wfield

Here, Wext is the external work done, ΔU is the change in the potential energy and Wfield is the work done on the field.

Therefore, the electric field does positive work when the charge −q moves closer to +Q.

(b)

To determine

Whether the potential −q move through a potential increase or decrease.

(b)

Expert Solution

Answer to Problem 1CQ

The potential increases as −q moves closer to +Q.

Explanation of Solution

The expression to find the potential is UE=kq1q2r12. The separation distance is inversely proportional to the potential. Thus as the charge moves closer, the potential increases.

Therefore, the potential increases as −q moves closer to +Q.

(c)

To determine

Whether the potential energy decreases or increases.

(c)

Expert Solution

Answer to Problem 1CQ

The potential energy decreases.

Explanation of Solution

For charges of opposite signs, the potential energy decreases due to the negative sign in the potential energy term. Thus, the potential energy decreases for two opposite signs approaching each other.

(d)

To determine

When the fixed charge is changed to −Q, the type of work done by the electric field, the change in potential and the change in potential energy.

(d)

Expert Solution

Answer to Problem 1CQ

The electric field does negative work, the potential decrease and the potential energy increases.

Explanation of Solution

When the charges are both negative, the electric field is doing negative work, the repulsion of the charges cause the potential to decrease and the potential energy increases.

Therefore, the electric field does negative work, the potential decrease and the potential energy increases.

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Phys 25

Answer 2

Question

Chapter 17, Problem 1CQ

(a)

To determine

Whether the electric field do positive or negative work when the charge −q moves closer to +Q.

(a)

Expert Solution

Answer to Problem 1CQ

The electric field does positive work when the charge −q moves closer to +Q.

Explanation of Solution

When we move two opposite charges close together, their initial and final kinetic energies will be zero, so the external force does negative work and the electric field does positive work.

Write the expression for the external work.

Wext=ΔU=−Wfield

Here, Wext is the external work done, ΔU is the change in the potential energy and Wfield is the work done on the field.

Therefore, the electric field does positive work when the charge −q moves closer to +Q.

(b)

To determine

Whether the potential −q move through a potential increase or decrease.

(b)

Expert Solution

Answer to Problem 1CQ

The potential increases as −q moves closer to +Q.

Explanation of Solution

The expression to find the potential is UE=kq1q2r12. The separation distance is inversely proportional to the potential. Thus as the charge moves closer, the potential increases.

Therefore, the potential increases as −q moves closer to +Q.

(c)

To determine

Whether the potential energy decreases or increases.

(c)

Expert Solution

Answer to Problem 1CQ

The potential energy decreases.

Explanation of Solution

For charges of opposite signs, the potential energy decreases due to the negative sign in the potential energy term. Thus, the potential energy decreases for two opposite signs approaching each other.

(d)

To determine

When the fixed charge is changed to −Q, the type of work done by the electric field, the change in potential and the change in potential energy.

(d)

Expert Solution

Answer to Problem 1CQ

The electric field does negative work, the potential decrease and the potential energy increases.

Explanation of Solution

When the charges are both negative, the electric field is doing negative work, the repulsion of the charges cause the potential to decrease and the potential energy increases.

Therefore, the electric field does negative work, the potential decrease and the potential energy increases.

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Answer 3

Question

Chapter 17, Problem 1CQ

(a)

To determine

Whether the electric field do positive or negative work when the charge −q moves closer to +Q.

(a)

Expert Solution

Answer to Problem 1CQ

The electric field does positive work when the charge −q moves closer to +Q.

Explanation of Solution

When we move two opposite charges close together, their initial and final kinetic energies will be zero, so the external force does negative work and the electric field does positive work.

Write the expression for the external work.

Wext=ΔU=−Wfield

Here, Wext is the external work done, ΔU is the change in the potential energy and Wfield is the work done on the field.

Therefore, the electric field does positive work when the charge −q moves closer to +Q.

(b)

To determine

Whether the potential −q move through a potential increase or decrease.

(b)

Expert Solution

Answer to Problem 1CQ

The potential increases as −q moves closer to +Q.

Explanation of Solution

The expression to find the potential is UE=kq1q2r12. The separation distance is inversely proportional to the potential. Thus as the charge moves closer, the potential increases.

Therefore, the potential increases as −q moves closer to +Q.

(c)

To determine

Whether the potential energy decreases or increases.

(c)

Expert Solution

Answer to Problem 1CQ

The potential energy decreases.

Explanation of Solution

For charges of opposite signs, the potential energy decreases due to the negative sign in the potential energy term. Thus, the potential energy decreases for two opposite signs approaching each other.

(d)

To determine

When the fixed charge is changed to −Q, the type of work done by the electric field, the change in potential and the change in potential energy.

(d)

Expert Solution

Answer to Problem 1CQ

The electric field does negative work, the potential decrease and the potential energy increases.

Explanation of Solution

When the charges are both negative, the electric field is doing negative work, the repulsion of the charges cause the potential to decrease and the potential energy increases.

Therefore, the electric field does negative work, the potential decrease and the potential energy increases.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 17, Problem 1CQ

(a)

To determine

Whether the electric field do positive or negative work when the charge −q moves closer to +Q.

(a)

Expert Solution

Answer to Problem 1CQ

The electric field does positive work when the charge −q moves closer to +Q.

Explanation of Solution

When we move two opposite charges close together, their initial and final kinetic energies will be zero, so the external force does negative work and the electric field does positive work.

Write the expression for the external work.

Wext=ΔU=−Wfield

Here, Wext is the external work done, ΔU is the change in the potential energy and Wfield is the work done on the field.

Therefore, the electric field does positive work when the charge −q moves closer to +Q.

(b)

To determine

Whether the potential −q move through a potential increase or decrease.

(b)

Expert Solution

Answer to Problem 1CQ

The potential increases as −q moves closer to +Q.

Explanation of Solution

The expression to find the potential is UE=kq1q2r12. The separation distance is inversely proportional to the potential. Thus as the charge moves closer, the potential increases.

Therefore, the potential increases as −q moves closer to +Q.

(c)

To determine

Whether the potential energy decreases or increases.

(c)

Expert Solution

Answer to Problem 1CQ

The potential energy decreases.

Explanation of Solution

For charges of opposite signs, the potential energy decreases due to the negative sign in the potential energy term. Thus, the potential energy decreases for two opposite signs approaching each other.

(d)

To determine

When the fixed charge is changed to −Q, the type of work done by the electric field, the change in potential and the change in potential energy.

(d)

Expert Solution

Answer to Problem 1CQ

The electric field does negative work, the potential decrease and the potential energy increases.

Explanation of Solution

When the charges are both negative, the electric field is doing negative work, the repulsion of the charges cause the potential to decrease and the potential energy increases.

Therefore, the electric field does negative work, the potential decrease and the potential energy increases.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 17, Problem 1CQ

(a)

To determine

Whether the electric field do positive or negative work when the charge −q moves closer to +Q.

(a)

Expert Solution

Answer to Problem 1CQ

The electric field does positive work when the charge −q moves closer to +Q.

Explanation of Solution

When we move two opposite charges close together, their initial and final kinetic energies will be zero, so the external force does negative work and the electric field does positive work.

Write the expression for the external work.

Wext=ΔU=−Wfield

Here, Wext is the external work done, ΔU is the change in the potential energy and Wfield is the work done on the field.

Therefore, the electric field does positive work when the charge −q moves closer to +Q.

(b)

To determine

Whether the potential −q move through a potential increase or decrease.

(b)

Expert Solution

Answer to Problem 1CQ

The potential increases as −q moves closer to +Q.

Explanation of Solution

The expression to find the potential is UE=kq1q2r12. The separation distance is inversely proportional to the potential. Thus as the charge moves closer, the potential increases.

Therefore, the potential increases as −q moves closer to +Q.

(c)

To determine

Whether the potential energy decreases or increases.

(c)

Expert Solution

Answer to Problem 1CQ

The potential energy decreases.

Explanation of Solution

For charges of opposite signs, the potential energy decreases due to the negative sign in the potential energy term. Thus, the potential energy decreases for two opposite signs approaching each other.

(d)

To determine

When the fixed charge is changed to −Q, the type of work done by the electric field, the change in potential and the change in potential energy.

(d)

Expert Solution

Answer to Problem 1CQ

The electric field does negative work, the potential decrease and the potential energy increases.

Explanation of Solution

When the charges are both negative, the electric field is doing negative work, the repulsion of the charges cause the potential to decrease and the potential energy increases.

Therefore, the electric field does negative work, the potential decrease and the potential energy increases.

Answer 6

Chapter 17, Problem 1CQ

(a)

To determine

Whether the electric field do positive or negative work when the charge −q moves closer to +Q.

(a)

Expert Solution

Answer to Problem 1CQ

The electric field does positive work when the charge −q moves closer to +Q.

Explanation of Solution

When we move two opposite charges close together, their initial and final kinetic energies will be zero, so the external force does negative work and the electric field does positive work.

Write the expression for the external work.

Wext=ΔU=−Wfield

Here, Wext is the external work done, ΔU is the change in the potential energy and Wfield is the work done on the field.

Therefore, the electric field does positive work when the charge −q moves closer to +Q.

Answer 7

Chapter 17, Problem 1CQ

(a)

To determine

Whether the electric field do positive or negative work when the charge −q moves closer to +Q.

Answer 8

(a)

Expert Solution

Answer to Problem 1CQ

The electric field does positive work when the charge −q moves closer to +Q.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

When we move two opposite charges close together, their initial and final kinetic energies will be zero, so the external force does negative work and the electric field does positive work.

Write the expression for the external work.

Wext=ΔU=−Wfield

Here, Wext is the external work done, ΔU is the change in the potential energy and Wfield is the work done on the field.

Therefore, the electric field does positive work when the charge −q moves closer to +Q.

Answer 13

(b)

To determine

Whether the potential −q move through a potential increase or decrease.

(b)

Expert Solution

Answer to Problem 1CQ

The potential increases as −q moves closer to +Q.

Explanation of Solution

The expression to find the potential is UE=kq1q2r12. The separation distance is inversely proportional to the potential. Thus as the charge moves closer, the potential increases.

Therefore, the potential increases as −q moves closer to +Q.

Answer 14

(b)

To determine

Whether the potential −q move through a potential increase or decrease.

Answer 15

(b)

Expert Solution

Answer to Problem 1CQ

The potential increases as −q moves closer to +Q.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

The expression to find the potential is UE=kq1q2r12. The separation distance is inversely proportional to the potential. Thus as the charge moves closer, the potential increases.

Therefore, the potential increases as −q moves closer to +Q.

Answer 20

(c)

To determine

Whether the potential energy decreases or increases.

(c)

Expert Solution

Answer to Problem 1CQ

The potential energy decreases.

Explanation of Solution

For charges of opposite signs, the potential energy decreases due to the negative sign in the potential energy term. Thus, the potential energy decreases for two opposite signs approaching each other.

Answer 21

(c)

To determine

Whether the potential energy decreases or increases.

Answer 22

(c)

Expert Solution

Answer to Problem 1CQ

The potential energy decreases.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

For charges of opposite signs, the potential energy decreases due to the negative sign in the potential energy term. Thus, the potential energy decreases for two opposite signs approaching each other.

Answer 27

(d)

To determine

When the fixed charge is changed to −Q, the type of work done by the electric field, the change in potential and the change in potential energy.

(d)

Expert Solution

Answer to Problem 1CQ

The electric field does negative work, the potential decrease and the potential energy increases.

Explanation of Solution

When the charges are both negative, the electric field is doing negative work, the repulsion of the charges cause the potential to decrease and the potential energy increases.

Therefore, the electric field does negative work, the potential decrease and the potential energy increases.

Answer 28

(d)

To determine

When the fixed charge is changed to −Q, the type of work done by the electric field, the change in potential and the change in potential energy.

Answer 29

(d)

Expert Solution

Answer to Problem 1CQ

The electric field does negative work, the potential decrease and the potential energy increases.

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

When the charges are both negative, the electric field is doing negative work, the repulsion of the charges cause the potential to decrease and the potential energy increases.

Therefore, the electric field does negative work, the potential decrease and the potential energy increases.