EBK MATHEMATICS FOR MACHINE TECHNOLOGY
EBK MATHEMATICS FOR MACHINE TECHNOLOGY
7th Edition
ISBN: 9780100548169
Author: SMITH
Publisher: YUZU
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Chapter 17, Problem 7AR
To determine

(a)

To evaluate the given expression.

Expert Solution
Check Mark

Answer to Problem 7AR

  516

Explanation of Solution

Given information:

An expression is given as 12×58

Calculation:

We have been given an expression as 12×58.

Evaluating the expression,

  12×58=1×52×8=516

Hence, 12×58=516.

To determine

(b)

To multiply the given fractions.

Expert Solution
Check Mark

Answer to Problem 7AR

  25

Explanation of Solution

Given information:

An expression is given as 34×45×23

Calculation:

We have been given an expression as 34×45×23.

Evaluating the expression,

  34×45×23=34×45×23=25

Hence, 34×45×23=25.

To determine

(c)

To evaluate the given expression.

Expert Solution
Check Mark

Answer to Problem 7AR

  1245256

Explanation of Solution

Given information:

An expression is given as 5732×38

Calculation:

We have been given an expression as 5732×38.

Evaluating the expression,

  5732×38=5×32+732×38=16732×38=501256=1245256

Hence, 5732×38=1245256.

To determine

(d)

To find the simplified value of given fractions.

Expert Solution
Check Mark

Answer to Problem 7AR

  102340

Explanation of Solution

Given information:

An expression is given as 3110×814

Calculation:

We have been given an expression as 3110×814.

Evaluating the expression,

  3110×814=3×10+110×8×4+14=3110×334=102340

Hence, 3110×814=102340.

To determine

(e)

To evaluate the given expression.

Expert Solution
Check Mark

Answer to Problem 7AR

  1658

Explanation of Solution

Given information:

An expression is given as 316×20×512

Calculation:

We have been given an expression as 316×20×512.

Evaluating the expression,

  316×20×512=316×20×5×2+12=316×20×112=34×4×4×5×112=1658

Hence, 316×20×512=1658.

To determine

(f)

To divide the given fractions.

Expert Solution
Check Mark

Answer to Problem 7AR

  34

Explanation of Solution

Given information:

An expression is given as 310÷25

Calculation:

We have been given an expression as 310÷25.

Evaluating the expression,

  310÷25=310×52=3×55×2×2=34

Hence, 310÷25=34.

To determine

(g)

To divide the given fractions.

Expert Solution
Check Mark

Answer to Problem 7AR

  34

Explanation of Solution

Given information:

An expression is given as 1415÷725

Calculation:

We have been given an expression as 1415÷725.

Evaluating the expression,

  1415÷725=1415×257=7×23×5×5×57=103

Hence, 1415÷725=103.

To determine

(h)

To find the simplified value of given expression.

Expert Solution
Check Mark

Answer to Problem 7AR

  48

Explanation of Solution

Given information:

An expression is given as 16÷13

Calculation:

We have been given an expression as 16÷13.

Evaluating the expression,

  16÷13=16×31=48

Hence, 16÷13=48.

To determine

(i)

To find the simplified value of given expression.

Expert Solution
Check Mark

Answer to Problem 7AR

  274

Explanation of Solution

Given information:

An expression is given as 21732÷924

Calculation:

We have been given an expression as 21732÷924.

Evaluating the expression,

  21732÷924=2×32+1732÷924=8132×249=9×98×4×8×39=274

Hence, 21732÷924=274.

To determine

(j)

To find the simplified value of given expression.

Expert Solution
Check Mark

Answer to Problem 7AR

  12532

Explanation of Solution

Given information:

An expression is given as 22932÷834

Calculation:

We have been given an expression as 22932÷834.

Evaluating the expression,

  22932÷834=2×32+2932÷8×4+34=9332÷334=3×318×4×43×11=3188

Hence, 22932÷834=3188.

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