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PRINCIPLES OF MODERN CHEMISTRY-OWLV2
8th Edition
ISBN: 9781305271609
Author: OXTOBY
Publisher: CENGAGE L
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Chapter 17, Problem 70P
the electroplating of a silver spoon, the spoon acts as thecathode and a piece of pure silver as the anode. Both dipinto a solution of silver cyanide (AgCN). Suppose that acurrent of 1.5 A is passed through such a cell for 22 minutesand that the spoon has a surface area of
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In addition to the separation techniques used in this lab (magnetism, evaporation, and filtering), there are other commonly used separation techniques. Some of these techniques are:Distillation – this process is used to separate components that have significantly different boiling points. The solution is heated and the lower boiling point substance is vaporized first. The vapor can be collected and condensed and the component recovered as a pure liquid. If the temperature of the mixture is then raised, the next higher boiling component will come off and be collected. Eventually only non-volatile components will be left in the original solution.Centrifugation – a centrifuge will separate mixtures based on their mass. The mixture is placed in a centrifuge tube which is then spun at a high speed. Heavier components will settle at the bottom of the tube while lighter components will be at the top. This is the technique used to separate red blood cells from blood plasma.Sieving – this is…
Chapter 17 Solutions
PRINCIPLES OF MODERN CHEMISTRY-OWLV2
Ch. 17 - Diagram the following galvanic cell, indicating...Ch. 17 - A galvanic cell is constructed in which a Br2Br+...Ch. 17 - A galvanic cell is constructed in which the...Ch. 17 - Prob. 67PCh. 17 - Galvanized steel consists of steel with a thin...Ch. 17 - the electroplating of a silver spoon, the spoon...Ch. 17 - In some old European churches, the stained-glass...Ch. 17 - Consider a galvanic cell for which the anode...
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- H HgSO4, H2O H2SO4arrow_forward12. Choose the best diene and dienophile pair that would react the fastest. CN CN CO₂Et -CO₂Et .CO₂Et H3CO CO₂Et A B C D E Farrow_forward(6 pts - 2 pts each part) Although we focused our discussion on hydrogen light emission, all elements have distinctive emission spectra. Sodium (Na) is famous for its spectrum being dominated by two yellow emission lines at 589.0 and 589.6 nm, respectively. These lines result from electrons relaxing to the 3s subshell. a. What is the photon energy (in J) for one of these emission lines? Show your work. b. To what electronic transition in hydrogen is this photon energy closest to? Justify your answer-you shouldn't need to do numerical calculations. c. Consider the 3s subshell energy for Na - use 0 eV as the reference point for n=∞. What is the energy of the subshell that the electron relaxes from? Choose the same emission line that you did for part (a) and show your work.arrow_forward
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