For the given titration curve of a weak base with a strong acid, The pH and the added volume of the base at the equivalence point is to be determined. The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and K a of the weak acid. The volume of added acid at which p H = 14 − p K b is to be determined. The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and K a of the conjugate acid. The volume of added acid is to be determined beyond which the volume of added acid is the pH calculated by concentrating on the amount of excess added strong acid.
For the given titration curve of a weak base with a strong acid, The pH and the added volume of the base at the equivalence point is to be determined. The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and K a of the weak acid. The volume of added acid at which p H = 14 − p K b is to be determined. The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and K a of the conjugate acid. The volume of added acid is to be determined beyond which the volume of added acid is the pH calculated by concentrating on the amount of excess added strong acid.
Interpretation: For the given titration curve of a weak base with a strong acid,
The pH and the added volume of the base at the equivalence point is to be determined.
The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and Ka of the weak acid.
The volume of added acid at which pH=14−pKb is to be determined.
The volume of the added acid is to be determined at which the volume of added acid is the pH calculated by working an equilibrium problem based on the initial concentration and Ka of the conjugate acid.
The volume of added acid is to be determined beyond which the volume of added acid is the pH calculated by concentrating on the amount of excess added strong acid.
we were assigned to dilute 900ppm
in to 18ppm by using only 250ml vol
flask. firstly we did calc and convert
900ppm to 0.9 ppm to dilute in 1 liter.
to begin the experiment we took
0,225g of kmno4 and dissolved in to
250 vol flask. then further we took 10
ml sample sol and dissolved in to 100
ml vol flask and put it in to a
spectrometer and got value of 0.145A
.
upon further calc we got v2 as 50ml
. need to find DF, % error (expval and
accptVal), molarity, molality. please
write the whole report. thank you
The format, tables, introduction,
procedure and observation, result,
calculations, discussion and
conclusion
Q5. Predict the organic product(s) for the following transformations. If no reaction will take place
(or the reaction is not synthetically useful), write "N.R.". Determine what type of transition state
is present for each reaction (think Hammond Postulate).
I
Br₂
CH3
F2, light
CH3
Heat
CH3
F₂
Heat
Br2, light
12, light
CH3
Cl2, light
No
None
Chapter 17 Solutions
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