BIG JAVA: LATE OBJECTS
2nd Edition
ISBN: 9781119626220
Author: Horstmann
Publisher: WILEY
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Chapter 17, Problem 5RE
Explanation of Solution
Tree:
- A data structure that is present in the hierarchical form and is composed of nodes.
- Each of the node will be having a sequence of child nodes and also one of the node is considered to be a root node.
Difference between the binary tree and binary search tree:
- Binary tree is a tree which can have maximum of two children.
- Binary search tree is a type of binary tree but with a constraints. The constraint for a binary tree to be a binary search tree:
- The left child of any node must have the value less than the value stored in the node and the right child must have the value greater than the value stored in the node.
Examples:
The example of both in the form of tree diagrams are shown below:
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Students have asked these similar questions
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 17 Solutions
BIG JAVA: LATE OBJECTS
Ch. 17.1 - Prob. 1SCCh. 17.1 - Prob. 2SCCh. 17.1 - Prob. 3SCCh. 17.1 - Prob. 4SCCh. 17.1 - Prob. 5SCCh. 17.1 - Prob. 6SCCh. 17.1 - Prob. 7SCCh. 17.2 - Prob. 8SCCh. 17.2 - Prob. 9SCCh. 17.2 - Prob. 10SC
Ch. 17.2 - Prob. 11SCCh. 17.2 - Prob. 12SCCh. 17.3 - Prob. 13SCCh. 17.3 - Prob. 14SCCh. 17.3 - Prob. 15SCCh. 17.3 - Prob. 16SCCh. 17.3 - Prob. 17SCCh. 17.3 - Prob. 18SCCh. 17.4 - Prob. 19SCCh. 17.4 - Prob. 20SCCh. 17.4 - Prob. 21SCCh. 17.4 - Prob. 22SCCh. 17.4 - Prob. 23SCCh. 17.4 - Prob. 24SCCh. 17.5 - Prob. 25SCCh. 17.5 - Prob. 26SCCh. 17.5 - Prob. 27SCCh. 17.5 - Prob. 28SCCh. 17.5 - Prob. 29SCCh. 17.5 - Prob. 30SCCh. 17.6 - Prob. 31SCCh. 17.6 - Prob. 32SCCh. 17.6 - Prob. 33SCCh. 17.6 - Prob. 34SCCh. 17.6 - Prob. 35SCCh. 17.7 - Prob. 36SCCh. 17.7 - Prob. 37SCCh. 17.7 - Prob. 38SCCh. 17.7 - Prob. 39SCCh. 17.7 - Prob. 40SCCh. 17 - Prob. 1RECh. 17 - Prob. 2RECh. 17 - Prob. 3RECh. 17 - Prob. 4RECh. 17 - Prob. 5RECh. 17 - Prob. 6RECh. 17 - Prob. 7RECh. 17 - Prob. 8RECh. 17 - Prob. 9RECh. 17 - Prob. 10RECh. 17 - Prob. 11RECh. 17 - Prob. 12RECh. 17 - Prob. 13RECh. 17 - Prob. 14RECh. 17 - Prob. 16RECh. 17 - Prob. 18RECh. 17 - Prob. 19RECh. 17 - Prob. 20RECh. 17 - Prob. 21RECh. 17 - Prob. 22RECh. 17 - Prob. 23RECh. 17 - Prob. 24RECh. 17 - Prob. 25RECh. 17 - Prob. 26RECh. 17 - Prob. 27RECh. 17 - Prob. 28RECh. 17 - Prob. 1PECh. 17 - Prob. 2PECh. 17 - Prob. 3PECh. 17 - Prob. 4PECh. 17 - Prob. 5PECh. 17 - Prob. 6PECh. 17 - Prob. 7PECh. 17 - Prob. 8PECh. 17 - Prob. 9PECh. 17 - Prob. 10PECh. 17 - Prob. 11PECh. 17 - Prob. 12PECh. 17 - Prob. 13PECh. 17 - Prob. 1PPCh. 17 - Prob. 2PPCh. 17 - Prob. 3PPCh. 17 - Prob. 4PPCh. 17 - Prob. 5PPCh. 17 - Prob. 6PPCh. 17 - Prob. 7PPCh. 17 - Prob. 8PPCh. 17 - Prob. 9PPCh. 17 - Prob. 10PPCh. 17 - Prob. 11PP
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